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Pavlova-9 [17]
3 years ago
15

Two male moose charge at each other with the same speed and meet on a icy patch of tundra. As they collide, their antlers lock t

ogether and they slide together with one-third of their original speed.
What is the ratio of their inertias?
Physics
2 answers:
Digiron [165]3 years ago
7 0

change in velocity of larger moose: (1/3)v - v = -(2/3)v

change in velocity of small moose: (1/3)v - (-v) = (4/3)v

(change in velocity of larger moose)/(change in velocity of smaller moose) = 2


Explanation:

It is the "ma" in F=ma that we tend to call inertia.Inertia is that the resistance of any entity to any amendment in its position and state of motion.

his includes changes to the object's speed, direction, or state of rest. Inertia is additionally outlined because the tendency of objects to stay getting a line at a continuing speed.

Ksenya-84 [330]3 years ago
4 0
Change in velocity of larger moose: (1/3)v - v = -(2/3)v 
<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>
<span>- (change in velocity of larger moose)/(change in velocity of smaller moose) = 2

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.



</span>
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Please help, and show steps. Thank you very much!
Vikentia [17]
V = 8 * 10^2 km/h = 800km/h
S= 1,8* 10^3 km = 1800km
t = ?
v = S/t
t = S/v
t = 1800km/ 800km/h
t ≈ 2,25h (135min)
6 0
3 years ago
Two large thin metal plates are parallel and close to each other. On their inner faces, the plates have excess surface charge of
wariber [46]

Answer:

For left = 0  N/C

For right = 0  N/C

At middle = -7.6836 * 10^{-11} \vec{i}  N/C

Explanation:

Given data :-

б =6.8 * 10^{-22} C/ m²

Considering the two thin metal plates to be non conducting sheets of charges.

Electric field is given by

E = \frac{\sigma }{2\varepsilon }

1) To the left of the plate

\vec{E}= (\frac{\sigma }{2\varepsilon })(-\vec{i})+  (\frac{\sigma }{2\varepsilon })(\vec{i})   = 0 N/C.

2) To the right of them.

\vec{E}= (\frac{\sigma }{2\varepsilon })(-\vec{i})+  (\frac{\sigma }{2\varepsilon })(\vec{i})   = 0 N/C.

3) Between them.

\vec{E}= (\frac{\sigma }{2\varepsilon })(-\vec{i})+  (\frac{\sigma }{2\varepsilon })(-\vec{i}) = (\frac{\sigma }{\varepsilon })(-\vec{i}) = -\frac{6.8 * 10^{-22} }{8.85 * 10 ^{-12} }  \vec{i} =   -7.6836 * 10^{-11} \vec{i} N/C

5 0
3 years ago
How would a neutral and positive ball react to eachother
cestrela7 [59]

Answer:

They would attract one another

Explanation:

The interaction between two like-charged objects is repulsive. ... Positively charged objects and neutral objects attract each other negatively charged objects and neutral objects attract each other.

8 0
2 years ago
What is the formula for kinetic energy
coldgirl [10]

Answer:

The formula for kinetic energy is K.E. = 1/2 mv 2 , where "m" stands for mass and "v" stands for velocity. Kinetic energy is typically measured in units of Joules, and 1 Joule is equal to 1 kilogram-meters squared per second squared.

Explanation:

8 0
3 years ago
Read 2 more answers
Four cylindrical wires of different sizes are made of the same material. Which of the following combinations of length and cross
anzhelika [568]

Answer:

Explanation:

For resistance of a wire , the formula is as follows .

R = ρ L/S

where ρ is specific resistance , L is length and S is cross sectional area of wire .

for first wire resistance

R₁ =  ρ 3L/3a = ρ L/a

for second wire , resistance

R₂ = ρ 3L/6a

= .5 ρ L/a

For 3 rd wire resistance

R₃ = ρ 6L/3a

= 2ρ L/a

For fourth wire , resistance

R₄ = ρ 6L/6a

=  ρ L/a

So the smallest resistance is of second wire .

Its resistance is .5 ρ L/a

7 0
3 years ago
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