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Pavlova-9 [17]
3 years ago
15

Two male moose charge at each other with the same speed and meet on a icy patch of tundra. As they collide, their antlers lock t

ogether and they slide together with one-third of their original speed.
What is the ratio of their inertias?
Physics
2 answers:
Digiron [165]3 years ago
7 0

change in velocity of larger moose: (1/3)v - v = -(2/3)v

change in velocity of small moose: (1/3)v - (-v) = (4/3)v

(change in velocity of larger moose)/(change in velocity of smaller moose) = 2


Explanation:

It is the "ma" in F=ma that we tend to call inertia.Inertia is that the resistance of any entity to any amendment in its position and state of motion.

his includes changes to the object's speed, direction, or state of rest. Inertia is additionally outlined because the tendency of objects to stay getting a line at a continuing speed.

Ksenya-84 [330]3 years ago
4 0
Change in velocity of larger moose: (1/3)v - v = -(2/3)v 
<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>
<span>- (change in velocity of larger moose)/(change in velocity of smaller moose) = 2

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.



</span>
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Answer:

n=2.9\times 10^9

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Explanation:

Given that

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A=2.8 x 10⁻¹¹ m²

v= 1 x 10⁻³  m/s

q= 2.8 x 10⁻¹⁴  m³/s

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Q= n q

n=Q/q

n=\dfrac{0.083\times 10^{-3} }{ 2.8\times 10^{-14}}

n=2.9\times 10^9

Surface  area A

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swat32
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Answer:

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Explanation:

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Answer:

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