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Pavlova-9 [17]
3 years ago
15

Two male moose charge at each other with the same speed and meet on a icy patch of tundra. As they collide, their antlers lock t

ogether and they slide together with one-third of their original speed.
What is the ratio of their inertias?
Physics
2 answers:
Digiron [165]3 years ago
7 0

change in velocity of larger moose: (1/3)v - v = -(2/3)v

change in velocity of small moose: (1/3)v - (-v) = (4/3)v

(change in velocity of larger moose)/(change in velocity of smaller moose) = 2


Explanation:

It is the "ma" in F=ma that we tend to call inertia.Inertia is that the resistance of any entity to any amendment in its position and state of motion.

his includes changes to the object's speed, direction, or state of rest. Inertia is additionally outlined because the tendency of objects to stay getting a line at a continuing speed.

Ksenya-84 [330]3 years ago
4 0
Change in velocity of larger moose: (1/3)v - v = -(2/3)v 
<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>
<span>- (change in velocity of larger moose)/(change in velocity of smaller moose) = 2

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.



</span>
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Simplify -2/3 - 3/5<br><br> A) -1/15<br><br> B) -19/15<br><br> C) -3/5<br><br> D) -5/8
Leto [7]
I got B,when you subtract 3/5 from NEGATIVE 2/3 it creates a negative 19 over a positive 15.

7 0
2 years ago
A flywheel in a motor is spinning at 590 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75
Gnom [1K]

Answer:

Explanation:

Hello,

Let's get the data for this question before proceeding to solve the problems.

Mass of flywheel = 40kg

Speed of flywheel = 590rpm

Diameter = 75cm , radius = diameter/ 2 = 75 / 2 = 37.5cm.

Time = 30s = 0.5 min

During the power off, the flywheel made 230 complete revolutions.

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + ω₂) / 2] × 0.5

But ∇θ = 230 revolutions

∇θ/t = (530 + ω₂) / 2

230 / 0.5 = (530 + ω₂) / 2

Solve for ω₂

460 = 295 + 0.5ω₂

ω₂ = 330rpm

a)

ω₂ = ω₁ + αt

but α = ?

α = (ω₂ - ω₁) / t

α = (330 - 590) / 0.5

α = -260 / 0.5

α = -520rev/min

b)

ω₂ = ω₁ + αt

0 = 590 +(-520)t

520t = 590

solve for t

t = 590 / 520

t = 1.13min

60 seconds = 1min

X seconds = 1.13min

x = (60 × 1.13) / 1

x = 68seconds

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + 0) / 2] × 1.13

∇θ = 333.35 rev/min

8 0
3 years ago
What is the moving kinetic energy of a 1500kg car moving at 25m/s?
EleoNora [17]

Answer:

<h2>468,750 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 1500 \times  {25}^{2}  \\  = 750 \times 625

We have the final answer as

<h3>468,750 J</h3>

Hope this helps you

4 0
2 years ago
A car travels a distance of 400 m in 5 seconds. Calculate its average velocity.
ikadub [295]

Answer:

80 m/s

Explanation:

x = 400 m

t = 5 s

x = vt,

400 = v(5),

80 = v

5 0
2 years ago
Read 2 more answers
The gravitational potential energy of an object is equal to its weight multiplied by its
Elina [12.6K]

Answer:

Height above a surface

Explanation:

Gravitational potential energy is the energy which an object possesses due to its position above a surface.

It is also the amount of work a force has to do in order to bring an object from a particular position to a point of reference.

It is given mathematically as:

P. E. = m*g*h

where m = mass of the body

g = acceleration due to gravity

h = height above a surface

m*g represents the weight of the object.

Hence, Gravitational potential energy is the product of an object's weight and its height above a surface/reference point.

3 0
3 years ago
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