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4 years ago

WILL GIVE BRAINLIEST

Physics

2 answers:

max2010maxim [7]4 years ago

5 0

D, the plant takes Solar/Light energy and converts it into chemical energy.

solniwko [45]4 years ago

4 0

Answer:

the answer is D Light energy is converted to chemical energy which in turn gives the plant glucose

Explanation:

i took the test

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A standard quantity of a physical property used as a factor to compare other occurring quantities of that property is called a(n

Brrunno [24]

The correct answer that would complete the given statement above would be option B. UNIT (of measurement). <span>A standard quantity of a physical property used as a factor to compare other occurring quantities of that property is called a unit of measurement. Hope this answers your question. </span>

3 0

3 years ago

The surface tension of water was determuned in a laboratory by using the drop weight method. 100 drops were released from a bure

lana [24]

Answer:

The surface tension of the water is 6.278×10⁻² N/m

error = 13.65%

Explanation:

The surface tension of water is given by

$\gamma = \frac{F}{L}$

Where F is the force acting on water and L is the length over which is force is acted.

We are given the mass of 100 droplets of water

M = 3.78 g

n = 100

The mass of 1 droplet is given by

$m = \frac{M}{n} \\\\m = \frac{3.78}{100}\\\\m = 0.0378 \: g \\\\m = 3.780\times10^{-5} \: kg$

The force acting on a single droplet of water is given by

$F = m \cdot g$

Where m is the mass of water droplet and g is the acceleration due to gravity

$F = 3.780\times10^{-5} \cdot 9.81$

$F = 3.708\times10^{-4} \: N$

The circumferential length of the droplet is given by

$L = \pi \cdot d$

Where d is the diameter

$L = \pi \cdot 1.88\times10^{-3}\\\\L = 5.906 \times10^{-3} \: m$

Now we can find out the required surface tension of the water

$\gamma = \frac{3.708\times10^{-4} }{5.906 \times10^{-3}} \\\\\gamma = 0.06278\: N/m\\\\\gamma = 6.278 \times10^{-2} \: N/m\\\\$

Therefore, the surface tension of the water is 6.278×10⁻² N/m

The tabulated value of the surface tension of water at 20 °C is given by

$\gamma_t = 0.0727 \: N/m$

The percentage error between tabulated and calculated surface tension is given by

$error = \frac{\gamma_t - \gamma }{\gamma_t}$

$error = \frac{ 0.0727 - 0.06278}{0.0727} \times 100\%$

$$ error = 13.65 \%$

7 0

3 years ago

What is the field outside the capacitor plates in a parallel capacitor?

FrozenT [24]

Answer is zero

Plz mark me brainlist

7 0

3 years ago

Read 2 more answers

Astronauts measure their mass by measuring the period of oscillation when sitting in a chair connected to a spring. The Body Mas

anzhelika [568]

Answer:

55 kg

Explanation:

spring constant (k) = 600 N/m

mass of chair (Mc) = 12 kg

period of oscillation of chair and man (T) = 2.1 s

what is the mass of the astronaut (Ma) ?

mass of the astronaut (Ma) = total mass (Mt) - mass of chair (Mc)

where

total mass (Mt) = $\frac{T^{2}}{4π^{2}}k$

taking π as 3.142

total mass (Mt) = $\frac{2.1^{2}}{4 x 3.142^{2}}600$

total mass (Mt) = 67 kg

therefore

mass of astronaut = 67 - 12 = 55 kg

4 0

3 years ago

dos contenedores de objetos tienen 30 y 40 kg de masa respectivamente y están sobre una superficie horizontal sin rozamiento una

Dmitry_Shevchenko [17]

Answer:

The acceleration of each mass is the same, and approximately equal to $1.43\,\,\frac{m}{s^2}$

Explanation:

Notice that the mass of the whole system is: 30 kg + 40 kg = 70 kg

If we use a net force of 100 N on the combined system, we can find the acceleration imparted to the masses via Newton's second law:

$F_{net}= M\,*\,a\\100\,\,N = 70\,\,kg * a\\a = \frac{100}{70} \,\frac{m}{s^2} \\a\approx 1.43\,\frac{m}{s^2}$

4 0

3 years ago