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Arisa [49]
3 years ago
11

How do trees stay please help

Chemistry
2 answers:
Amanda [17]3 years ago
4 0

Answer:

Because they have strong roots, they remain stuck in the ground.

Explanation:Because they have strong roots, they remain stuck in the ground.

tensa zangetsu [6.8K]3 years ago
4 0

Answer:

They stay stuck to the ground by roots

Explanation:

I hope that was what you were looking for

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How does Gregor Mendel's work with pea plants affect human life today? OA A. People continue to cross pea plants to fix Mendel's
lana [24]

Answer:

B

Explanation:

Not sure, but that one makes the most since

4 0
3 years ago
Hospital patients are administered oxygen from an pressurized
VashaNatasha [74]

Answer:

32000atm

Explanation:

Using Boyle's law equation;

P1V1 = P2V2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (

V2 = final volume (L)

According to the question below:

P1 = 160.0 atm

P2 = 3.0 atm

V1 = 600L

V2 = ?

Using P1V1 = P2V2

160 × 600 = 3 × V2

96000 = 3V2

V2 = 96000/3

V2 = 32000atm

5 0
2 years ago
What is the oxidation number of sulfur in H2SO3?<br> a. +3<br> b. +1<br> c. +2<br> d. +4
Alla [95]
We need to keep in mind that the compound is neutral.

H2SO3
2(+1)+S+3(-2)=0 (since its neutral)
2+S-6=0
S-4=0
S=4

Therefore the oxidation number for sulfur is +4.
3 0
3 years ago
Read 2 more answers
What is the difference between mass and weight?
Olin [163]

Explanation:

The mass of an object is a measure of the object's inertial property, or the amount of matter it contains. The weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it. The pull of gravity on the earth gives an object a downward acceleration of about 9.8 m/s2.

7 0
2 years ago
A quantity of 0.225 g of a metal M (molar mass = 27.0 g/mol) liberated 0.303 L of molecular hydrogen (measured at 17°C and 741 m
Lana71 [14]

Answer:

Oxide of M is M_2O_3 and sulfate of M_2(SO_4)_3

Explanation:

0.303 L of molecular hydrogen gas measured at 17°C and 741 mmHg.

Let moles of hydrogen gas be n.

Temperature of the gas ,T= 17°C =290 K

Pressure of the gas ,P= 741 mmHg= 0.9633 atm

Volume occupied by gas , V = 0.303 L

Using an ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.9633 atm\times 0.303 L}{0.0821 atm L/mol K\times 290 K}=0.01225 mol

Moles of hydrogen gas produced = 0.01225 mol

2M+2xHCl\rightarrow 2MCl_x+xH_2

Moles of metal =\frac{0.225 g}{27.0 g/mol}=8.3333 mol

So, 8.3333 mol of metal M gives 0.01225 mol of hydrogen gas.

\frac{8.3333}{0.01225 mol}=\frac{2}{x}

x = 2.9 ≈ 3

2M+6HCl\rightarrow 2MCl_3+3H_2

MCl_3\rightarrow M^{3+}+Cl^-

Formulas for the oxide and sulfate of M will be:

Oxide of M is M_2O_3 and sulfate of M_2(SO_4)_3.

3 0
3 years ago
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