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3 years ago

How do trees stay please help

Chemistry

2 answers:

Amanda [17]3 years ago

4 0

Answer:

Because they have strong roots, they remain stuck in the ground.

Explanation:Because they have strong roots, they remain stuck in the ground.

tensa zangetsu [6.8K]3 years ago

4 0

Answer:

They stay stuck to the ground by roots

Explanation:

I hope that was what you were looking for

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1. Is air a mixture or a compound?<br> mixture

Mekhanik [1.2K]

Its mixture goodluck :)

8 0

2 years ago

Read 2 more answers

What is the possible formula of AC if A has 2 valence electrons and C has 7 valence electron?

Brut [27]

AC2

A will lose 2
C will gain 1

Need two Cs to match A

3 0

2 years ago

The subshell letter:a) specifies the 3-D shape of the orbital.b) specifies the principal shell of the orbital.c) specifies the p

Dafna11 [192]

Answer:

a) specifies the 3-D shape of the orbital

Explanation:

To determine the region where is more probable to find the electron, it is characterized by four quantum numbers:

- Principal quantum number (n): represents the level, or shell, where the electron is. It varies from 1 to 7, and are represented by the letters K, L, M, N, O, P, and Q.

-Azimuthal quantum number (l): represents the sublevel, or subshell. Is represented by the letters s, p, d, f, g, ... And by the numbers 0, 1, 2, 3, ... Each one has a 3-D shape, the s, for example, has a spherical shape.

-Magnetic quantum number (ml): represents the orbital inside the subshell, and varies from -l to +l, passing by the 0. Each orbital can have at least 2 electrons.

-Spin quantum number (ms): represents the spin of the electron, which can be +1/2 or -1/2.

3 0

3 years ago

CHEMISTRY HELP<br> Once the following equation is balanced, what is the correct coefficient for Z₂?

yawa3891 [41]

Answer:

The coefficient of Z₂ is 1.

Explanation:

From the question given above:

X + ZY —> XY + Z₂

Next, we shall balance the equation to obtain the coefficient of Z₂. This can be obtained as follow:

X + ZY —> XY + Z₂

There is 1 atom of Z on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of ZY as shown below:

X + 2ZY —> XY + Z₂

There are 2 atoms of Y on the left side and 1 atom on the right side. It can be balance by putting 2 in front of XY as shown below:

X + 2ZY —> 2XY + Z₂

Now, we have 1 atom of X on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of X as shown below:

2X + 2ZY —> 2XY + Z₂

Now the equation is balanced.

Thus, the coefficient of Z₂ is 1.

8 0

2 years ago

Aspirin (acetylsalicylic acid, C9H8O4) is a weak monoprotic acid. To determine its acid-dissociation constant, a student dissolv

Triss [41]

Answer:

1. $3.57\times 10^{-4}$ was the $K_a$ value calculated by the student.

2. $5.93\times 10^{-4}$ was the $K_b$ of ethylamine value calculated by the student.

Explanation:

The $pH$ value of Aspirin solution = 2.62

$pH=-\log[H^+]$

$[H^+]=10^{-2.62}=0.00240 M$

Moles of s asprin = $\frac{2.00 g}{180 g/mol}=0.01111 mol$

Volume of the solution = 0.600 L

The initial concentration of Aspirin = c = $\frac{0.01111 mol}{0.600 L}=0.0185 M$

$HAs\rightleftharpoons As^-+H^+$

initially

c 0 0

At equilibrium

(c-x) x x

The expression of dissociation constant :

$K_a=\frac{[As^-][H^+]}{[HAs]}$ :

$K_a=\frac{x\times x }{(c-x)}$

$=\frac{0.00240 M\times 0.00240 M}{(0.0185-0.00240 )}$

$K_a=3.57\times 10^{-4}$

$3.57\times 10^{-4}$ was the $K_a$ value calculated by the student.

The $pH$ value of ethylamine = 11.87

$pH+pOH=14$

$pOH=14-11.87=2.13$

$pOH=-\log[OH^-]$

$[OH^-]=10^{-2.13}=0.00741 M$

The initial concentration of ethylamine = c = 0.100 M

$C_2H_5NH_2+H_2O\rightleftharpoons C_2H_5NH_3^{+}+OH^-$

initially

c 0 0

At equilibrium

(c-x) x x

The expression of dissociation constant :

$K_b=\frac{[C_2H_5NH_3^{+}][OH^-]}{[C_2H_5NH_2]}$ :

$K_b=\frac{x\times x}{(c-x)}$

$=\frac{0.00741\times 0.00741}{(0.100-0.00741)}$

$K_b=5.93\times 10^{-4}$

$5.93\times 10^{-4}$ was the $K_b$ of ethylamine value calculated by the student.

3 0

3 years ago