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3 years ago

How do trees stay please help

Chemistry

2 answers:

Amanda [17]3 years ago

4 0

Answer:

Because they have strong roots, they remain stuck in the ground.

Explanation:Because they have strong roots, they remain stuck in the ground.

tensa zangetsu [6.8K]3 years ago

4 0

Answer:

They stay stuck to the ground by roots

Explanation:

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BRAINLIEST Give examples of at least three critical questions of society that science can help answer.

ICE Princess25 [194]

Answer:

1. How did life begin?

2. Are we alone in the universe?

3. What makes us human?

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3 years ago

What is a food web made up of

brilliants [131]

Answer:

A food web is made up of all the food chains in a single ecosystem. Each living thing in an ecosystem belongs to many food chains. A food chain is a path that energy takes through a certain ecosystem. Trophic Levels. Organisms in food webs are grouped into categories called trophic levels.

Explanation:

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2 years ago

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Which of the following displays the correct change in enthalpy and best describes the reaction below? 2CsCl(aq) + Na2SO4(aq) 2Na

Bond [772]

We subtract the enthalpies of the reactants from that of the products:
$2\Delta
 H(NaCl)+\Delta H(Cs_2 SO_4)-2\Delta H(CsCl)-\Delta H(Na_2 SO_4) \\ 
=2(-411)+(-1400) -2(-415)-(-1380) \\ = -12 kJ$
Since this is < 0, this is an exothermic reaction.

3 0

3 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 Pb(ClO3)2 with aqueous NaI . NaI. Include phases. chemica

FinnZ [79.3K]

<u>Answer:</u> The mass of precipitate (lead (II) iodide) that will form is 119.89 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI solution = 0.130 M

Volume of solution = 0.400 L

Putting values in above equation, we get:

$0.130M=\frac{\text{Moles of NaI}}{0.400L}\\\\\text{Moles of NaI}=(0.130mol/L\times 0.400L)=0.52mol$

The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

The precipitate (insoluble salt) formed is lead (II) iodide

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 0.52 moles of NaI will produce = $\frac{1}{2}\times 0.52=0.26mol$ of lead (II) iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of lead (II) iodide = 0.26 moles

Molar mass of lead (II) iodide = 461.1 g/mol

Putting values in above equation, we get:

$0.26mol=\frac{\text{Mass of lead (II) iodide}}{461.1g/mol}\\\\\text{Mass of lead (II) iodide}=(0.26mol\times 461.1g/mol)=119.89g$

Hence, the mass of precipitate (lead (II) iodide) that will form is 119.89 grams

4 0

3 years ago

2 AICI3 + 3 Ca - 3 CaCl2 + 2 Al

Aleksandr [31]

Answer:

50 gram calcium do you need

Explanation:

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5 0

3 years ago