The answer is true.
An example is cyclohexane.
Answer: The equilibrium concentration of 
will be much smaller than the equilibrium concentration of 
, because Keq<<1
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.
For the given chemical reaction:
The expression for is written as:
![K=\frac{[H_3O^+]\times [BrO^-]}{[HBrO]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5Ctimes%20%5BBrO%5E-%5D%7D%7B%5BHBrO%5D%7D)
Concentration of pure solids and liquids is taken as 1.
Thus as 
, That means the concentration of products is less as the reaction does not proceed much towards the forward direction.
Answer:Temperature affects storage time and food deteriorates faster at higher temperatures. Microorganisms grow rapidly at room temperature . Thus to slow microbial growth, enzymatic and oxidative processes, food must be stored at room temperature.
Due to decomposition reactions with oxygen or carbon dioxide in the air, meat begins to feel slimy and smell spoiled. ... Because of its smaller surface area, the unsliced meat would have less collisions and therefore, a slower reaction rate.
Explanation:
The empirical formula : C₁₂H₄F₇
The molecular formula : C₂₄H₈F₁₄
<h3>Further explanation</h3>
mol C (MW=12 g/mol)
mol H(MW=1 g/mol) :
mol F(MW=19 g/mol)
mol ratio of C : H : O =1.52 : 0.51 : 0.89=3 : 1 : 1.75=12 : 4 : 7
Empirical formula : C₁₂H₄F₇
(Empirical formula)n=molecular formula
( C₁₂H₄F₇)n=562 g/mol
(12.12+4.1+7.19)n=562
(281)n=562⇒ n =2
Molecular formula : C₂₄H₈F₁₄
<h3>1. <u>Answer</u>;</h3>
= 5.4×10-6 g AgBr
<h3><u>Explanation</u>;</h3>
AgBr(s) → Ag+(aq) + Br-(aq) Ksp = 3.3×10^-13
[Ag+][Br-] = Ksp = 3.3×10^-13 = X²
X = 5.7×10^-7 M = [Ag+] = mol/L AgBr that dissolve
1 mole of AgBr = 187.8 g
Therefore;
= 0.05 L × (5.7 × 10^-7 mol/L) × (187.8 g /mol)
= 5.4×10-6 g AgBr
<h3>2. <u>Answer and explanation;</u></h3>
The two factors that accounts for increased rate of chemical reaction when temperature is increased are:
- <u>Energy factor</u>; enough energy in the collision for the formation of an activated complex, where bonds are breaking and new ones forming. When temperature is increased, a greater number of molecular collisions possess enough energy to activate the reaction.
- <u>Frequency of collisions increases;</u> an increase in temperature makes particles move faster and collide more frequently, increasing the possibility of a reaction be-tween them.
More important factor; Energy factor is more important.
