3.47 x 
atoms of gold have mass of 113.44 grams.
Explanation:
Data given:
number of atoms of gold = 3.47 x
mass of the gold in given number of atoms = ?
atomic mass of gold =196.96 grams/mole
Avagadro's number = 6.022 X
from the relation,
1 mole of element contains 6.022 x atoms.
so no of moles of gold given = 
0.57 moles of gold.
from the relation:
number of moles = 
rearranging the equation,
mass = number of moles x atomic mass
mass = 0.57 x 196.96
mass = 113.44 grams
thus, 3.47 x atoms of gold have mass of 113.44 grams
Answer: 4.4
Explanation:
Thats what my computer says after i submit answer
Answer:
heterogeneous mixture or a chemical mixture
As we know that Molarity is given as,
M = moles / V
Solving for V,
V = moles / M ------------------(1)
Also, moles is equal to,
moles = mass / M. mass -------------(2)
puting value of moles from eq. 2 into eq. 1,
V = (mass / M.mass) / M
Putting values,
V = (45 g / 164 g/mol) / 1.3 mol/dm³
V = 0.21 dm³
Molar mass:
( Br₂ ) = 159.80 g/mol
AlCl₃ = 133.34 g/mol
<span>2 AlCl</span>₃<span> + 3 Br</span>₂<span> = 2 AlBr</span>₃<span> + 3 Cl</span>₂
2 x ( 133.34) g ------------ 3 x ( 159.80) g
11.95 ------------------------ ( mass Bromine )
mass Bromine = 11.95 x 3 x 159.80 / 2 x 133.34
mass Bromine = 5728.83 / 266.68
mass Bromine = 21.48 g
hope this helps!
