<span>To determine the pH of the solution given, we make
use of the acid equilibrium constant (Ka) given. It is the ratio of the
equilibrium concentrations of the dissociated ions and the acid. The
dissociation reaction of the CH3COOH acid would be as follows:
</span>CH3COOH = CH3COO- + H+<span>
The acid equilibrum constant would be expressed as follows:
Ka = [H+][</span>CH3COO-] / [CH3COOH] = 1.8× 10^–5
<span>
To determine the equilibrium concentrations we use the ICE table,
CH3COOH H+ </span>CH3COO<span>-
I 1.60 0 0
C -x +x +x
----------------------------------------------------------------
E 1.60-x x x
</span>1.8× 10^–5 = [H+][CH3COO-] / [CH3COOH] <span>
1.8 x 10^-5 = [x][x] / [0.160-x] </span>
Solving for x,
x = 1.69x10^-3 = [H+] = [F-]
pH = -log [H+] = -log [1.69x10^-3] = 2.8
Answer : Group 14 elements are likely to have substances that have both metal and non-metallic properties.
Explanation :
Metalloid : It is a type of element whose properties lies in between the metals and non-metals.
There are commonly six metalloids : Boron(group 13), Silicon & Germanium(group 14), Arsenic & Antimony(group 15), Tellurium(group 16).
Properties of Metalloids :
- Metalloids look like metals but behave largely like non-metals.
- Metalloids are solid, brittle and lustrous.
- Metalloids has ability to conduct electricity.
Therefore, Group 14 elements are likely to have substances that have both metal and non-metallic properties.
Answer:
(a) pH = 1.0
(b) pH = 7.0
(c) 60 mL
Explanation:
(a) At the start of the titration there's no OH⁻ species yet.
pH = -log[H⁺]
And because HCl is a strong acid
[H⁺] = [HCl] = 0.1 M
Thus
pH = -log (0.1) = 1.0
(b) In every strong base-strong acid titration, the pH at the equivalence point is 7.0.
(c) Because<em> the concentration of HCl and NaOH are the same</em>, you would need<u> 30 mL of the NaOH solution to neutralize 30 mL of the HCl solution</u>, thus the total volume is 60 mL.
Answer:
Work = 90.65 j
Explanation:
Given data:
Mass = 0.500 Kg
Distance = 18.5 m
Work done = ?
Solution:
Work = force . distance
Force = mg
Work = mg.distance
Work = mgh
Work = 0.500 Kg × 9.8 m/s²× 18.5 m
Work = 90.65 Kg .m²/s²
Kg .m²/s² = j
Work = 90.65 j
Answer:
Chemists keep track of how electrons are transferred between atoms in a reaction using an oxidation number. If the oxidation number of an element in the reaction increases or becomes less negative, the element has been oxidized, while a decreased or more negative oxidation number means the element has been reduced.
