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stellarik [79]
3 years ago
15

Which of the following groups of elements are likely to have substances that have both metal and non-metallic properties?

Chemistry
2 answers:
Tom [10]3 years ago
4 0

Answer : Group 14 elements are likely to have substances that have both metal and non-metallic properties.

Explanation :

Metalloid : It is a type of element whose properties lies in between the metals and non-metals.

There are commonly six metalloids : Boron(group 13), Silicon & Germanium(group 14), Arsenic & Antimony(group 15), Tellurium(group 16).

Properties of Metalloids :

  • Metalloids look like metals but behave largely like non-metals.
  • Metalloids are solid, brittle and lustrous.
  • Metalloids has ability to conduct electricity.

Therefore, Group 14 elements are likely to have substances that have both metal and non-metallic properties.


Digiron [165]3 years ago
4 0

Answer:

group 14

Explanation:

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Explanation:

Danish physicist Niels Bohr proposed an atomic model for the hydrogen atom which was later extended to other elements. Its model is based on the Solar System, in which the planets rotate around the sun. For Bohr, electrons rotate in orbit around the atomic nucleus grouped into energy levels.

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8 0
4 years ago
Please help! Ionic and covalent compound.
mrs_skeptik [129]
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25) Ionic
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27) Ionic ?
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29) Ionic ?
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31) Ionic ?
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These answers are based on if there was a nonmetal and nonmetal it’s Covalent and if there was a metal and nonmetal it was Ionic I didn’t use the electro negativity for the answers that has more than two elements, if the answers had more than two elements they have a ? Next to their answer.

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2 years ago
What is the change in internal energy for each of the following situations? 1. q-7.9 J out of the system and w 3.6 J done on the
adoni [48]

Answer:

A i. Internal energy ΔU = -4.3 J ii. Internal energy ΔU = -6.0 J B. The second system is lower in energy.

Explanation:

A. We know that the internal energy,ΔU = q + w where q = quantity of heat and w = work done on system.

1. In the above q = -7.9 J (the negative indicating heat loss by the system). w = 3.6 J (It is positive because work is done on the system). So, the internal energy for this system is ΔU₁ = q + w = -7.9J + 3.6J = -4.3 J

ii. From the question q = +1.5 J (the positive indicating heat into the system). w = -7.5 J (It is negative because work is done by the system). So, the internal energy for this system is ΔU₂ = q + w = +1.5J + (-7.5J) = +1.5J - 7.5J = - 6.0J

B. We know that ΔU = U₂ - U₁ where U₁ and U₂ are the initial and final internal energies of the system. Since for the systems above, the initial internal energies U₁ are the same, then we say U₁ = U. Let U₁ and U₂ now represent the final energies of both systems in A i and A ii above. So, we write ΔU₁ = U₁ - U and ΔU₂ = U₂ - U where ΔU₁ and ΔU₂ are the internal energy changes in A i and A ii respectively. Now from ΔU₁ = U₁ - U, U₁ = ΔU₁ + U and U₂ = ΔU₂ + U. Subtracting both equations U₁ - U₂ = ΔU₁ - ΔU₂

= -4.3J -(-6.0 J)= 1.7 J. Since U₁ - U₂ > 0 , U₂ < U₁ , so the second system's internal energy increase less and is lower in energy and is more stable.

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olga_2 [115]
Answer is 0.7 g

Reason: Given: mass of Fe = 5.60 gWe know that, half life of Fe-53 = t1/2 (Fe-53) = 8.51 min.
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Amount left after third half-life = 1.40g/2 = 0.7g.
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