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exis [7]
3 years ago
8

Please help I need this Now

Chemistry
1 answer:
frez [133]3 years ago
5 0

The above figure is example of system equilibrium because it is closed system.

In closed system there's no loss of product (or reactant) therefore equilibrium is established.

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If an electron travels at a velocity of 1.000 x 107 m/s and has a mass of 9.109 x 10-28 g, what is its wavelength?
alina1380 [7]
Good luck i don’t even know
3 0
3 years ago
Is mixing butter, granulated sugar, and brown sugar until it's creamy a physical or chemical change and why
Nadusha1986 [10]

Answer:

Physical

Explanation: Because it says "Until creamy" meaning you're changing the look, not the way it reacts with each other.

8 0
3 years ago
Read 2 more answers
What is the amount of heat released by 1.00 gram of liquid water at 0°C when it changes to 1.00 gram of ice at 0°C?
QveST [7]

Answer:

334J/g

Explanation:

Data obtained from the question include:

Mass (m) = 1g

Specific heat of Fusion (Hf) = 334 J/g

Heat (Q) =?

Using the equation Q = m·Hf, we can obtain the heat released as follow:

Q = m·Hf

Q = 1 x 334

Q = 334J

Therefore, the amount of heat released is 334J

8 0
4 years ago
A balloon filled with helium gas at 1.00 atm occupies 12.9 L. What volume would the balloon occupy in the upper atmosphere, at a
Taya2010 [7]

Answer:

67,9 L

Explanation:

Boyle's Law indicates that the pressure of a fixed amount of gas at a constant temperature is inversely proportional to the volume of a gas, for a constant amount of gas we can write:

P1V1=P2V2

For the problem:

P1= 1 atm, V1= 12,9 L

P2=0,19 atm, V2=?

Therefore:

V2=P1V1/P2.................... V2=1 atm*12,9L/0,19 atm = 67,9 L

The balloon would occupy a volume of 67,9 L in the upper atmosphere.

5 0
3 years ago
If 45.0 mL of ethanol (density =0.789g/mol) initially at 6.0°C mix with 45.0 mL of water (density =1.0 g/mol) initially at 28.0°
Likurg_2 [28]

The final temperature of the mixture : 21.1° C  

<h3>Further explanation  </h3>

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released  

Q in(gained) = Q out(lost)  

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

Q ethanol=Q water

mass ethanol=

\tt mass=\rho\times V\\\\mass=0.789\times 45=35.505~g

mass water =

\tt mass=1~g/ml\times 45~ml=45~g

then the heat transfer :

\tt 35.505\times 2.42~J/g^oC\times (t-6)=45\times 4.18~J/g^oC\times (28-t)\\\\85.922t-515.533=5266.8-188.1t\\\\274.022t=5782.33\rightarrow t=21.1^oC

5 0
3 years ago
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