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timurjin [86]
3 years ago
8

A government has a single-employer defined benefit pension plan for the employees of its Electric Utility Enterprise Fund. On De

cember 31, 2020, the government had a total pension liability for the plan of $1,300,000 and accumulated pension plan assets to pay the liability of $780,000. The assets to pay the liability are reported as a part of the Enterprise Fund's unrestricted fund balance. Assuming no pension liability had been recorded in the Enterprise Fund on December 31, 2019 and there is no pension related deferred inflows or outflows of resources, what journal entry does the government need to make to record the government's pension liability on December 31, 2020 in its Enterprise Fund?
Business
1 answer:
Natasha_Volkova [10]3 years ago
4 0

AnswerEnterprise Fund Dr. 1,300,000

Pension Fund CR. 1,300,000

Narration recognition of outstanding pension fund.

Note This will throw the Enterprise fund into a deficit of $520,000

To provide for the deficit

Income Dr. 520,000

Enterprise fund CR 520,000

Narration. Recognition of pension not covered by asset.

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Part a) The Cob Douglas production function is given as:

Q(K,L)=AK^{1.4} L^ {1.6 } .

To show that this function is homogeneous with degree 3, we introduce be a parameter, t.

Q(tK,tL)=A(tK)^{1.4} (tL)^ {1.6 } .

Using properties of exponents, we on tinder:

Q(tK,tL)=At^{1.4}K^{1.4} t^ {1.6 }L^ {1.6 } .

This implies that:

Q(tK,tL)=t^{1.4} \times t^ {1.6 }(AK^{1.4} L^ {1.6 } )

Q(tK,tL)=t^{1.4 + 1.6}(AK^{1.4} L^ {1.6 } )

Simplify the exponent of t to get;

Q(tK,tL)=t^{3}(AK^{1.4} L^ {1.6 } )

Hence the function is homogeneous with degree, 3

Part b) To verify Euler's Theorem, we must show that:

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L}=3AK^{1.4}L^{1.6}

Verifying from the left:

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =K(1.4AK^{0.4} L^{1.6}) + L(1.6AK^{1.4} L^{0.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =1.4(AK^{1.4} L^{1.6}) + 1.6(AK^{1.4} L^{1.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =(1.4 +  1.6)(AK^{1.4} L^{1.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =3(AK^{1.4} L^{1.6})

Q•E•D

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