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leva [86]
3 years ago
8

PLEASE HELP!!!!!!!!!! DOING A TEST

Chemistry
2 answers:
Arturiano [62]3 years ago
6 0

Answer:

answer is D) carbohydrates

Nastasia [14]3 years ago
4 0
D is the correct answer
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Write a balanced half-reaction for the oxidation of aqueous hydrazine N2H4 to gaseous nitrogen N2 in basic aqueous solution
Zigmanuir [339]

Answer:

N2H2(aq) + 2OH^-(aq) ----------> N2(g) + 2H2O(l) + 2e

Explanation:

Hydrazine is mostly used in thermal engineering as an anticorrosive agent. Hydrazine can be oxidized in aqueous solution as shown in the equation above. Oxidation has to do with loss of electrons and increase in oxidation number.

The oxidation number of nitrogen in the equation increased from -1 in hydrazine on the lefthand side of the reaction equation to zero in nitrogen on the right hand side of the reaction equation. Two electrons were lost in the process as shown.

7 0
3 years ago
What are the three was main States of matter?
OleMash [197]

Answer:

liquid, solid, gas

Explanation:

7 0
4 years ago
Read 2 more answers
What is the pressure in a 24.0-LL cylinder filled with 32.7 gg of oxygen gas at a temperature of 319 KK? Express your answer to
Blizzard [7]

Answer:

The pressure in that cylinder = 1.12atm

Explanation:

We use general gas law to calculate it. General gas law is gotten by combining Boyle's law, Charles' law and Avogadro's law. Thus

P = nRT/V

Where n = number of moles

R = the gas constant

T is the Temperature, V is the volume and P is the pressure.

Given: T = 319K, V = 24L, R = 0.0821 L.atm/K.mol

The first step is to find n using

n = mass of O2/molar mass of O2

=32.7/32

=1.0219

Now, using P =nRT/V

P = 1.0219 ×0.0821×319÷24

Therefore P = 1.12atm

8 0
3 years ago
What volume (mL) of concentrated solution of magnesium chloride (9.00 M) must be diluted to 350. mL to make a 2.75 M solution of
zalisa [80]

❤Answer

<u>Volume </u><u>of</u><u> 106.9 mL from the concentrated solution should be taken and diluted to 350 </u><u>mL.</u>

⠀

⠀

<u>Main I'd On Indian Brainly Is - HeartCrush</u>

⚡ Explantion

<u>We can use the </u><u>formula.</u><u> </u>

c1v1 =c2v2

<u>Where c1 is the concentration and v1 is volume of the concentrated </u><u>solution.</u><u> </u>

c2 is the concentration

and v2 is the volume of the diluted solution to be prepared

9.00 M x V1 = 2.75 M x 350 mL

V1 = 106.9 mL

<u>Volume of 106.9 mL from the concentrated solution should be taken and diluted to 350 </u><u>mL</u><u>.</u>

3 0
3 years ago
If a strong base, like NaOH, is added to a strong acid, like HCl, the pH of the resultant solution will _________. A.) Go up B.)
MakcuM [25]

Answer:

B.) Go down

Explanation:

Hello,

In this case, a strong base like NaOH has a high pH based on the scale wherein 7 is neutral, above 7 is basic and below 7 is acid. In such a way, by adding an acid, having a low pH, once it is added, the pH will go down until the equivalence point, which for strong base and strong acid should be 7.

Best regards.

7 0
4 years ago
Read 2 more answers
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