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VARVARA [1.3K]
3 years ago
6

Why is density considered a physical property rather than a chemical property of matter?

Chemistry
1 answer:
Harrizon [31]3 years ago
3 0
Because density is mass and all mass is Physical.
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Scientists have developed the Atomic Theory over a period of hundreds of years. What will help us further the development? A. in
stepladder [879]

Answer:

A. increasing the ability of technology, like microscopes, to see even smaller particles

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3 years ago
Which temperature in Celsius (°C) does this thermometer show? –8° 0° 25° 32°
natka813 [3]

Answer:

0° Celsius

Explanation:

The thermometer shows 0° Celsius which corresponds to 32° F.

3 0
3 years ago
Which solution is a homogeneous mixture?
r-ruslan [8.4K]
Within the categories of homogeneous and heterogeneous mixtures there are more specific types of mixturesincluding solutions, alloys, suspensions, and colloids. A solutionis a mixture where one of the substances dissolves in the other. The substance that dissolves is called the solute.
6 0
3 years ago
Read 2 more answers
Please please please help
weqwewe [10]

Answer:

See explanation.

Explanation:

Hello!

In this case, since the main molecular reaction that is taken place in the beaker is:

AgNO_3(aq)+BaI_2(aq)\rightarrow AgI(s)+Ba(NO_3)_2(aq)

In such a way, we understand that one breaker contained silver nitrate and the other one barium iodide. Thus, the complete molecular equations turns out:

2AgNO_3(aq)+BaI_2(aq)\rightarrow 2AgI(s)+Ba(NO_3)_2(aq)

Now, for the complete ionic equation, we just ionize the aqueous species:

2Ag^++2NO_3^-+Ba^{2+}+2I^-\rightarrow 2AgI(s)+Ba^{2+}+2(NO_3)^-

Finally, for the net ionic equation we cancel out barium and nitrate ions as the spectator one because they are both sides on the equation:

2Ag^++2I^-\rightarrow 2AgI(s)

Best regards!

3 0
3 years ago
help plz really need your help if u know answer if u don't DO NOT ANSWER this is not the first time I have posted this question​
morpeh [17]

T eg(1) : 97.5°C, T eg(2): 98.5°C, T eg(3): 99.2°C

∆T water(1): -2.5°C, ∆T water(2): -1.5°C, ∆T water(3): -0.8°C

∆T metal(1): 77.5°C, ∆T metal(2): 80.5°C, ∆T metal(3): 80.2°C.

ft= (m1 cp1 t1 + m2 cp2 t2 + .... + mn cpn tn) / (m1 cp1 + m2 cp2 + .... + mn cpn) (1)

where,

1000g = 1kg

ft(t eg)= final mixed temperature (°C)

m = mass of substance (kg)

cp = specific heat of substance (J/kg°C)

t = temperature of substance (°C)

6 0
3 years ago
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