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3 years ago

What happens if you don't use enough solvent for a recrystallization?

1 answer:

6 0

<span>With too little solvent, recrystallization occurs too quickly due to massive nucleation upon the flask becoming cooler. The crystals do not grow fully in this shortened period of time, as the solvent precipitates before the reaction is complete. Nucleation of the crystals also means more impurities in the final product.. .</span>

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How do elements on the right side of the periodic table differ from elements on the left side of the table?

lozanna [386]

The answer is c.

Elements on the left side of the table are metals, such as sodium, lithium, potassium, etc.

Elements on the right side are non metals, such as Chlorine, Fluorine, Bromine, etc.

4 0

3 years ago

How much heat (in kilojoules) is evolved or absorbed in the reaction of 1.90 g of na with h2o? 2na(s) 2h2o(l)→2naoh(aq) h2(

myrzilka [38]

Do you have a screen shot or picture of the problem?

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3 years ago

How many grams are in 1.76 x 10^23 atoms of iodine

Mariana [72]

Answer:

$\boxed {\boxed {\sf About \ 37.1 \ grams \ of \ iodine }}$

Explanation:

To convert from atoms to grams, you must first convert atoms to moles, then moles to grams.

1. Convert Atoms to Moles

To convert atoms to grams, Avogadro's number must be used.

$6.022*10^{23}$

This number tells us the number of particles (atoms, molecules, ions, etc.) in 1 mole. In this case, the particles are atoms of iodine.

$\frac{6.022*10^{23} \ atoms \ I }{1 \ mol \ I}$

Multiply the given number of atoms by Avogadro's number.

$1.76*10^{23} \ atoms \ I*\frac{6.022*10^{23} \ atoms \ I }{1 \ mol \ I}$

Flip the fraction so the atoms of iodine will cancel out.

$1.76*10^{23} \ atoms \ I*\frac{ 1 \ mol \ I}{6.022*10^{23} \ atoms \ I}$

$1.76*10^{23}* \frac{1 \ mol \ I}{6.022*10^{23} }$

Multiply so the problem condenses into 1 fraction.

$\frac{1.76*10^{23} \ mol \ I}{6.022*10^{23} }$

$0.2922617071 \ mol \ I$

2. Convert Moles to Grams

Now we must use the molar mass of iodine, which is found on the Periodic Table.

Iodine Molar Mass: 126.9045 g/mol

Use this mass as a fraction.

$\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}$

Multiply this fraction by the number of moles found above.

$0.2922617071 \ mol \ I*\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}$

Multiply. The moles of iodine will cancel.

$0.2922617071 *\frac{ 126.9045 \ g\ I }{ 1 }$

The 1 as a denominator is insignificant.

$0.2922617071 *{ 126.9045 \ g\ I }$

$37.08932581 \ g \ I$

3. Round

The original measurement of 1.76*10^23 has 3 significant figures (1, 7, and 6). Therefore we must round our answer to 3 sig figs. For this answer, that is the tenths place.

$37.08932581 \ g \ I$

The 8 in the hundredth place tells us to round the 0 up to a 1.

$\approx 37.1\ g \ I$

There is about <u>37.1 grams of iodine </u>in 1.76*10^23 atoms.

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3 years ago

15.True or False:

Nadusha1986 [10]

True
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2 years ago

sample of saline contains 45 ml of saline in 128 ml of water. What is the percent by volume of the solution?

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3 years ago