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3 years ago

Which set of statements best explains the relationship between the parts of the respiratory system?

Chemistry

1 answer:

Ivanshal [37]3 years ago

3 0

Answer:

The description of that same scenario is listed mostly in the explanation portion following.

Explanation:

This same respiratory system involves several lungs, as well as the systemic circulation concerning this same human heart, which operates in conjunction to pick up more oxygen as well as expel CO2 from the body.

These same lungs encourage O2 to pass both through alveoli via the blood capillaries surrounding off the front of the alveoli, that are otherwise interconnected to the arterial circulation, which carries O2 rich blood something to human heart through which O2 rich blood was indeed transported to many other blood vessels via the artery
Consequently, those system works together to promote the transmission of gas throughout tissues and organs and also to ensure sustainable the tissue functions required during metabolic functions.

You might be interested in

How many moles of na+ are present in 343 ml of a 1.27 m solution of na2so4?

cricket20 [7]

Sodium sulfate, Na₂SO₄, is a strong electrolyte. It means that it dissociates into 2 Na⁺ ions and 1 SO₄⁻ ion when dissolved in water. So, for every 1 mole of Na₂SO₄, there is an equivalent amount of 2 mol Na⁺ ions. The solution is as follows:

Moles of Na⁺ = (1.27 mol Na₂SO₄/L)*(1 L/1000 mL)*(343 mL)*(2 mol Na⁺/1 mol Na₂SO₄)
Moles of Na⁺ = 0.87 mol

4 0

4 years ago

Which of the following is used to calculate the distance to a star based on subtle shifts in the star's position relative to an

Nana76 [90]

Parrallax is used to calculate the distance.

8 0

4 years ago

Click on the alignment to view it at a larger size. Scan along the aligned sequences, letter by letter, noting any positions whe

miss Akunina [59]

Answer:

8 amino acids

Explanation:

Amino acids are referred to as organic compounds containing carboxylic acid functional groups and amine. Amino acids contain different elements such as nitrogen, hydrogen, carbon and oxygen. Examples of amino acids are glycine, glutamic acid and alanine. In the given alignment, there are 8 amino acids between the sequence of human and monkey.

3 0

4 years ago

What is the molarity of a solution prepared by diluting 250 mL of a 40% H2SO4 solution to 1 Liter? The density of the stock solu

kiruha [24]

Answer:

1.195 M.

Explanation:

We can calculate the concentration of the stock solution using the relation:

M = (10Pd)/(molar mass).

Where, M is the molarity of H₂SO₄.

P is the percent of H₂SO₄ (P = 40%).

d is the density of H₂SO₄ (d = 1.17 g/mL).

molar mass of H₂SO₄ = 98 g/mol.

∴ M of stock H₂SO₄ = (10Pd)/(molar mass) = (10)(40%)(1.17 g/mL) / (98 g/mol) = 4.78 M.

We have the role that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.

∴ (MV) before dilution = (MV) after dilution

M before dilution = 4.78 M, V before dilution = 250 mL.

M after dilution = ??? M, V after dilution = 1.0 L = 1000 mL.

∴ M after dilution = (MV) before dilution/(V after dilution) = (4.78 M)(250 mL)/(1000 mL) = 1.195 M.

3 0

3 years ago

One gram-mole of methyl chloride vapor is contained in a vessel at 100°C and 10atm.(a) Use the ideal-gas equation of state to es

777dan777 [17]

Answer:

a) The volume of the system is 3.062 Liters.

b) Percentage error results from assuming ideal-gas behavior is 9.36%.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = $10 atm$

V = Volume of gas = ?

n = number of moles of gas = 1 mol

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 100°C = 100+273K=373 K

Putting values in above equation, we get:

$(10 atm)\times V=1 mol\times (0.0821L.atm/mol.K)\times 373 K$

$V=\frac{1 mol\times (0.0821L.atm/mol.K)\times 373 K}{10 atm}$

V = 3.062 L

The volume of the system is 3.062 Liters.

Volume of the container = V' = 2.8 L

System volume = V = 3.062 L

Percentage error of volume:

To calculate the percentage error, we use the equation:

$\%\text{ error}=\frac{|\text{Experimental value - Accepted value}|}{\text{Accepted value}}\times 100$

$=\frac{|3.062L-2.8 L|}{2.8 L}\times 100=9.36\%$

Percentage error results from assuming ideal-gas behavior is 9.36%.

6 0

3 years ago