Question

What is the solution set of the equation j+4/j+2=2−1/j ? Note: j≠0, −2

Answer 1

Answer:

 values of j are: 2 , -1

Step-by-step explanation:

We have been given:

$\frac{j+4}{j+2}={2}-\frac{1}{j}$

We will cross multiply in the above equation we get:

$\frac{j+4}{j+2}=\frac{2j-1}{j}$

$j^2+4j=2j^2+4j-j-2$

$2j^2-j^2+4j-4j-j-2$

$j^2-j-2$

We will solve the quadratic equation by factorizing:

$j^2-2j+j-2$

$j(j-2)+1(j-2)$

$(j+1)(j-2)$

hence, the values of j are: 2 , -1