Answer:
Death, Destruction, Loss of home
Answer:
Uniform acceleration means that the object is accelerating at a constant rate. Since there is still acceleration, velocity is not constant. In fact, the velocity is increasing. This means that the object is moving faster and faster at a constant rate.
This graph is a displacement-time graph so its gradient would represent the velocity of the object. The velocity increases hence the gradient should increase (which means that the graph must be steeper and steeper with increasing time).
Constant gradient of a displacement-time graph would mean that there is no acceleration since gradient of the graph does not change so velocity is constant.
Note that it is the<em> </em><em>rate</em><em> </em><em>of</em><em> </em><em>change</em> of velocity that is constant during uniform acceleration, not velocity.
Answer:
hey
Explanation:
I'm a bts army are u also army?
Answer:
a = 4.9(1 - sinθ - 0.4cosθ)
Explanation:
Really not possible without a complete setup.
I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g
F = ma
mg - mgsinθ - μmgcosθ = (m + m)a
mg(1 - sinθ - μcosθ) = 2ma
½g(1 - sinθ - μcosθ) = a
maximum acceleration is about 2.94 m/s² when θ = 0
acceleration will be zero when θ is greater than about 46.4°