As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1
As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.
Given, a△b=a^2-b/b-a^2
now 4△3 = (4^2-3) / (3-4^2)
4△3 = (16-3) / (3-16)
4△3 = 13 / -13
4△3 = -1
Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.
- Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.
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Answer:
117.5 or 235/2
Step-by-step explanation:
We can set up an equation for this problem:
Lets Joe's weight be x
then:
2x -5 = 230
therefore:
2x = 235
x = 117.5 or 235/2
Answer:
It's the second box.
Step-by-step explanation:
There, you are getting the most product for the cheapest.
Well to find the range, you need to take the highest number and subtract the lowest from it:
3 - -97
3 + 97
100
Range is always positive
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Answer:
96
Step-by-step explanation:
Find the prime factorization of 12
12 = 2 × 2 × 3
Find the prime factorization of 32
32 = 2 × 2 × 2 × 2 × 2
Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM:
LCM = 2 × 2 × 2 × 2 × 2 × 3
LCM = 96
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