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UkoKoshka [18]
3 years ago
9

A gear and shaft with nominal diameter of 34 mm are to be assembled with a medium drive fit (H7/s6). The gear has a hub, with an

outside diameter of 45 mm, and an overall length of 50 mm. The shaft is made from AISI 1020 CD steel, and the gear is made from steel that has been through hardened to provide Su = 700 MPa and Sy = 600 MPa. a) Specify dimensions with tolerances for the shaft and gear bore to achieve the desired fit. b) Determine the minimum and maximum pressures that could be experienced at the interfaces with the specified tolerances. c) Determine the worst-case static factors of safety guarding against yielding at assembly for the shaft and the gear based on Von-Mises failure theory. d) Determine the maximum torque that the joint should be expected to transmit without slipping.

Engineering
1 answer:
mylen [45]3 years ago
4 0

Answer:

Explanation:

Given that :

Nominal size (d) = 34 mm ,

specification : Medium drive fit .

Outside diameter (d) =45 mm

Length (l) = 50 mm

Material Specification : AISI 1020 CD steel

Tensile strength = 700 MPa

Yield strength = 600 MPa

Yield strength of steel =390 MPa

See attachment for the explanation

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2 years ago
Which system of linear inequalities is represented by the graph? y &gt; x – 2 and y x + 1 y x + 1 y &gt; x – 2 and y &lt; x + 1
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Answer:

The graph representing the linear inequalities is attached below.

Explanation:

The inequalities given are :

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For tables for values of x and y and get coordinates to plot for both equation.

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5 0
3 years ago
Read 2 more answers
I will mark as brainliest !
Sliva [168]

Answer:

7.8 Mph

Explanation:

Rate of cycling = 1.1 rev/s

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Diameter of sprocket on pedal = 6 inches

Diameter of sprocket on rear wheel = 4 inches

Circumference of rear wheel =  \pi d=26\piπd=26π

Speed would be

\begin{gathered}\text{Rate of cycling}\times \frac{\text{Diameter of sprocket on pedal}}{\text{Diameter of sprocket on rear wheel}}\times{\text{Circumference of rear wheel}}\\ =1.1\times \frac{6}{4}\times 26\pi\\ =134.77432\ inches/s\end{gathered}Rate of cycling×Diameter of sprocket on rear wheelDiameter of sprocket on pedal×Circumference of rear wheel=1.1×46×26π=134.77432 inches/s

Converting to mph

1\ inch/s=\frac{1}{63360}\times 3600\ mph1 inch/s=633601×3600 mph

134.77432\ inches/s=134.77432\times \frac{1}{63360}\times 3600\ mph=7.65763\ mph134.77432 inches/s=134.77432×633601×3600 mph=7.65763 mph

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3 years ago
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