A gear and shaft with nominal diameter of 34 mm are to be assembled with a medium drive fit (H7/s6). The gear has a hub, with an
outside diameter of 45 mm, and an overall length of 50 mm. The shaft is made from AISI 1020 CD steel, and the gear is made from steel that has been through hardened to provide Su = 700 MPa and Sy = 600 MPa. a) Specify dimensions with tolerances for the shaft and gear bore to achieve the desired fit. b) Determine the minimum and maximum pressures that could be experienced at the interfaces with the specified tolerances. c) Determine the worst-case static factors of safety guarding against yielding at assembly for the shaft and the gear based on Von-Mises failure theory. d) Determine the maximum torque that the joint should be expected to transmit without slipping.
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Answer:
Stat PVC = Stat(82+98.5)
Stat PVT = Stat(59+71.5)
Explanation
PVI = 71 + 35
Let G1 = Grade 1; G2 = Grade 2
G1 = +2.1% ; G2 = -3.4%
Highest point of curve at station = 74 + 10
General equation of a curve:
At highest point of the curve
Station PVT
Explanation:
Specific cutting energy:
It the ratio of power required to cut the material to metal removal rate of material.If we take the force required to cut the material is F and velocity of cutting tool is V then cutting power will be the product of force and the cutting tool velocity.
Power P = F x V
Lets take the metal removal rate =MRR
Then the specific energy will be
If we consider that metal removal rate and cutting tool velocity is constant then when we increases the cutting force then specific energy will also increase.