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sdas [7]
3 years ago
5

A 5 MW gas turbine power plant is reported to have a thermodynamic efficiency of 35%. Assume products of the combustion reaction

exit at 750K with water in the gaseous phase. a. What is the corresponding heat rate of the power cycle
Engineering
1 answer:
sineoko [7]3 years ago
4 0

Answer:

The corresponding heat rate of the power cycle is  9749 BTU/kWh

Explanation:

Heat rate is the common measure of system efficiency in a steam power plant. It is defined as "the energy input to a system, typically in Btu/kWh, divided by the electricity generated, in kW."

Heat rate (BTU/kWh) = (Input Energy. Btu/hr)/(output power. kW)

Given;

Electrical energy output of gas turbine power plant = 5 MW = 5000 KW

Chemical energy input of the turbine = ?

Also, Efficiency = output power/input power

Given, efficiency = 35% = 0.35

0.35 = 5000 kW/input power

Input Power (kW) = 5000/0.35

Input Power (kW) = 14,285.7 KW

1 KW = 3412.142 BTU/hr

14,285.7 KW =   48,744,836.97 BTU/hr

Heat rate (BTU/kWh) = (Input Energy. Btu/hr)/(output power. kW)

Heat rate (BTU/kWh) = (48,744,836.97 BTU/hr)/(5000 KW)

Heat rate (BTU/kWh) = 9748.97 BTU/kWh = 9749 BTU/kWh

Therefore, the corresponding heat rate of the power cycle is  9749 BTU/kWh

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Answer:

Explanation: Clutch Plate.

Clutch Cover.

Clutch Bearing (Release bearing)

Release Fork (clutch fork)

7 0
2 years ago
Under which of the following conditions is a Type B-1 Fire extinguisher required onboard a motorized vessel?
swat32

Answer:

The correct option is;

D. The vessel has closed living spaces onboard

Explanation:

Type B-1 Fire extinguishers

A fire extinguisher is required by the law to be installed in a boat that hs the following specifications

1) There are closed compartment in the boat that can be used for fuel storage

2) There exist double double bottom that is only partially filled with flotation materials

3) There are closed living spaces in the boat

4) The fuel tank is permanently installed in the boat

5) The engine is inboard.

7 0
4 years ago
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Amiraneli [1.4K]
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4 0
3 years ago
Which of the following conditions is a good sign of minor
Kryger [21]

Answer:

Explanation:

d

7 0
3 years ago
A water pump delivers 3 hp of shaft power when operating. If the pressure differential between the outlet and the inlet of the p
Natali [406]

Answer:

Mechanical Efficiency =  83.51%

Explanation:

Given Data:

Pressure difference = ΔP=1.2 Psi

Flow rate = V=8ft^3/s\\

Power of Pump = 3 hp

Required:

Mechanical Efficiency

Solution:

We will first bring the change the units of given data into SI units.

P=1.2*6.895 = 8.274KPa\\V=8*0.00283=0.226 m^3/s\\P=3*0.746=2.238KW

Now we will find the change in energy.

Since it is mentioned in the statement that change in elevation (potential energy) and change in velocity (Kinetic Energy) are negligible.

Thus change in energy is

=(Mass * change in P)/density\\= \frac{M*P}{p}\\\\

As we know that Mass = Volume x density

substituting the value

Energy = Volume * density x ΔP / density

Change in energy = Volumetric flow x ΔP

Change in energy = 0.226 x 8.274 = 1.869 KW

Now mechanical efficiency = change in energy / work done by shaft

Efficiency = 1.869 / 2.238

Efficiency = 0.8351 = 83.51%

5 0
3 years ago
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