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3 years ago

Only answer this if your name is riley

Engineering

2 answers:

Fittoniya [83]3 years ago

8 0

Explanation: im not a reiley but thx for points BiG bRaIn PlaYz

Sati [7]3 years ago

3 0

Answer:

hey im like kinda riley

Explanation:

y u wanna talk to moi

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Zanzabum

D IS THE ANSWER ❤︎❤︎❤︎spread love and share knowledge

3 0

3 years ago

You’ve experienced convection cooling if you’ve ever extended your hand out the window of a moving vehicle or into a flowing wat

Anna35 [415]

Answer:

Condition A

Heat flux is 1400 W/M^2

Condition B

Heat flux is 12800 w/m^2

Explanation:

Given that:

$T_s$ is given as 30 degree celcius

condition A

Air temperature = - 5 degree c

convection coefficient h = 40 w/m^2. k

$heat\ flux = \frac{Q}{a}= h\Delta = 40{30 - (-5)} = 1400 w/m^2$

condition A

water temperature = 10 degree c

convection coefficient = 800 w/m^2.k

$heat\ flux = \frac{Q}{A} = H(\Delta} = 800\times (30-14) = 12800w/m^2$

7 0

3 years ago

Water flows around a 6-ft diameter bridge pier with a velocity of 12 ft/s. Estimate the force (per unit length) that the water e

jolli1 [7]

Answer: hello the diagram related to your question is missing please the third image is the missing part of the question

Fx = 977.76 Ib/ft

Explanation:

<u>Estimate the force that water exerts on the pier </u>

V = 12 ft/s

D( diameter ) = 6 ft

first express the force on the first half of the cylinder as

Fx1 = - $-2\int\limits^\pi _\frac{\pi }{2} {Ps*cos\beta *a} \, d\beta$ ---------------- ( 1 )

where ; Fy = 0

Ps = Po + 1/2 Pv^2 ( 1 - 4 sin^2β ) ------------- ( 2 )

Input equation (2) into equation ( 1 ) (note : assuming Po = 0 )

attached below is the remaining part of the solution

3 0

3 years ago

An add tape of 101 ft is incorrectly recorded as 100 ft for a 200-ft distance. What is

baherus [9]

Answer:

the correct distance is 202 ft

Explanation:

The computation of the correct distance is shown below:

But before that correction to be applied should be determined

= (101 ft - 100 ft) ÷ (100 ft) × 200 ft

= 2 ft

Now the correct distance is

= 200 ft + 2 ft

= 202 ft

Hence, the correct distance is 202 ft

The same would be relevant and considered too

4 0

3 years ago

The 40-ft-long A-36 steel rails on a train track are laid with a small gap between them to allow for thermal expansion. Determin

vfiekz [6]

Answer:

Ф = 0.02838 ft

F = 1,032 N

Explanation:

To find out gap delta,

As it is case of free thermal expansion,

First we start with, some assumptions we have to made to solve this problem.

1. Thermal Expansion Coefficient of Steel is ∝= 6.45 ×10^(-6)

2. Modulas of elasticity for A-36 steel is E= 200 GPa

3. Area of rail is assumed to be unit area.

The gape required can be given by,

Ф = ∝ × ΔT × L ... where Ф= Gap Delta in ft

ΔT= Temperature rise in F

= 90- (-20)

= 110 F

Ф = 6.45 ×10^(-6) × 110 × 40

Ф = 28,380 × 10^(-6) ft

Ф = 0.02838 ft .... total gape required for expansion of steel rails

Stress induced in rails is given by,

σ = ∝ × ΔT × E

= 6.45 ×10^(-6) × 110 × 200

σ = 1,41,900 Pa

Now, let's find axial force in rails,

Here,we have to consider ΔT= 20 F.

As due to temperature change, axial force generated in rails can be find by,

F = A × ∝ × ΔT× E × L

F = 1 × 6.45 × 10^(-6) × 20 × 200 × 10^(-9) × 40

F = 25,800 × 40 × 10^(-3)

F = 10,32,000 × 10^(-3)

F= 1,032 N

Finally, due to temperature change, rail is subjected to axial force, axial stress.

8 0

3 years ago