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3 years ago

Only answer this if your name is riley

Engineering

2 answers:

Fittoniya [83]3 years ago

8 0

Explanation: im not a reiley but thx for points BiG bRaIn PlaYz

Sati [7]3 years ago

3 0

Answer:

hey im like kinda riley

Explanation:

y u wanna talk to moi

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What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 5 × 10-4

White raven [17]

Answer:

The question is a problem that requires the principles of fracture mechanics.

and we will need this equation below to get the Max. Stress that exist at the tip of an internal crack.

Explanation:

Max Stress, σ = 2σ₀√(α/ρ)

where,

σ₀ = Tensile stress = 190MPa = 1.9x10⁸Pa

α = Length of the cracked surface = (4.5x10⁻²mm)/2 = 2.25x10⁻⁵m

ρ = Radius of curvature of the cracked surface = 5x10⁻⁴mm = 5x10⁻⁷m

Max Stress, σ = 2 x 1.9x10⁸ x (2.25x10⁻⁵/5x10⁻⁷)⁰°⁵

Max Stress, σ = 2 x 1.9x10⁸ x 6.708 Pa

Max Stress, σ = 2549MPa

Hence, the magnitude of the maximum stress that exists at the tip of an internal crack = 2549MPa

7 0

4 years ago

Using only the sequential operations described in Section 2.2.2, write an algorithm that gets two values: the price for item A a

suter [353]

Answer:

total_cost = cost + tax

Explanation:

Step1) Let the 2 variable for take input from user e.g price and quantity

var price ;

var quantity ;

var cost ;

var tax ;

var total_cost ;

Step2) take input from user quantity of item 'A'

step3) cost = price * quantity

Step4) tax = 0.08 * cost

Step5) total_cost = cost + tax

Step6) print the total_cost

7 0

3 years ago

HELP PLS

Angelina_Jolie [31]

Answer:

The correct option is;

B) Metamorphic Rocks

Explanation:

Zoisite, which is also referred to saualpite, is a metamorphic rock which is a hydroxy sorosilicate mineral formed from other types of rocks such as sedimentary, metamorphic and ingenious rocks in the process of their metamorphism under the presence high temperatures and pressures and mineral fluids which are hot

Zoiste is named after Sigmund Zois by Abraham Gottlob Werner in 1805 when Sigmund Zois sent Abraham Gottlob Werner the mineral specimen from Saualpe in 1805

6 0

3 years ago

An inventor claims to have developed a power cycle operating between hot and cold reservoirs at 1350 K and 295 K, respectively,

Art [367]

Answer:

efficiency = 0.71999 < 0.78148

efficiency = 0.7999 ≈ 0.78148

Explanation:

given data

Hot reservoir Temp Th = 1350 K

Cold reservoir Temp Tc = 295 K

heat transfer rate = 150,000 kJ/h

solution

first we get here maximum possible efficiency that is express as

maximum possible efficiency = 1 - $\frac{Tc}{Th}$ ..........1

put here value and we get

maximum possible efficiency = 1 - $\frac{295}{1350}$

maximum possible efficiency = 0.78148

and

efficiency = $\frac{Wout}{Qin}$ .................2

here Qin = $\frac{150000}{3600}$ = 41.667

so put here value in equation 2 we get

efficiency = $\frac{30}{41.667}$

efficiency = 0.71999 < 0.78148

and

efficiency = $\frac{33.33}{41.667}$

efficiency = 0.7999 ≈ 0.78148

claim might be true or not because there always be looser

5 0

4 years ago

Implement this C program by defining a structure for each payment. The structure should have at least three members for the inte

Klio2033 [76]

Answer:

#include<stdio.h>

#include<math.h>

void output_amortized(float loan_amount,float intrest_rate,int term_years)

{

int i,j; //Month

int payments; //Number of payments

float loanAmount; //Loan amount

float anIntRate; //Yealy interest Rate

float monIntRate; //Monthly interest rate

float monthPayment; //Monthly payment

float balance; //Balance due

float monthPrinciple; //Monthly principle paid

float monthPaidInt; //Month interest paid

balance=loan_amount;

//Calculations

//Monthly interest rate

monIntRate = ((intrest_rate/(100*12)));

//Monthly payment

payments=term_years;

monthPayment = (loan_amount * monIntRate * (pow(1+monIntRate, payments)/(pow (1+monIntRate, payments)-1)));

monthPaidInt = balance * monIntRate;

//Amount paid to principle

monthPrinciple = monthPayment-monthPaidInt;

//New balance due

balance = balance - monthPrinciple;

printf("\n\nMonthly payment should be :%.2f\n\n",monthPayment);

printf("============================AMORTIZATION SCHEDUAL==========================\n");

printf("#\tPayment\t\tIntrest\t\tPrinciple\t\tBalance\n");

for(i=0;i<payments;i++)

{

printf("%d%9c%.2f%9c%.2f%16c%.2f%14c%.2f\n",(i+1),'$',monthPayment,'$',monthPaidInt,'$',monthPrinciple,'$',balance);

monthPaidInt = balance * monIntRate;

//Amount paid to principle

monthPrinciple = monthPayment-monthPaidInt;

//New balance due

balance = balance - monthPrinciple;

}

int main()

{

float principle,rate;

int termYear;

printf("Enter the loan amount: $");

scanf("%f",&principle);

printf("Enter the intrest rate :%");

scanf("%f",&rate);

printf("Enter the loan duration in years: ");

scanf("%d",&termYear);

output_amortized(principle,rate,termYear);

}

Explanation:

see output

6 0

3 years ago