Answer: y = R*sin(2.75*t - δ)
Here δ is just the time offset and for our purposes is pretty irrelevant. You can in fact set it to zero since we can say we begin timing when the mass crosses equilibrium. So
y = R*sin(2.75*t)
We want to find a way to use the information "At the equilibrium position, it moves 2.89 m/s." I am going to use some calculus here since it makes things so much easier. If you haven't taken calculus yet, most likely your course has given you a formula to use instead.
We know y=0 when t=0, so y is at equilibrium when t=0. To say it moves 2.89 m/s is then to say that
y'(0) = 2.89.
From here we can differentiate the displacement function, set t=0 and solve for R. Using the chain rule:
y'(t) = 2.75*R*cos(2.75*t)
y'(0) = 2.75*R
2.75*R = 2.89
R = 1.051
Explanation: Since this is harmonic motion we can assume there is no damping force. The frequency of the oscillation is given by ω=√(k/m)=√(18.9/2.5)=2.75. Keep in mind this is angular frequency, i.e. radians per second, not wavelengths per second.
Answer:
a1
b2
d3
c5
d4
Explanation:
Hope this helps
Check if right by the way
Answer:
You need to know the accuracy to which you can read the ruler:
Suppose that you can read the read the ruler to the nearest milimeter
A = L * W your calculated area of the rectangle
A + ΔA = (L + ΔL) * (W + ΔW) = L W + L ΔW + W * ΔL + ΔL ΔA
Or ΔA = L ΔW + W ΔL
Where we have subtracted A = L * W and the term ΔL * ΔA is very small
So (5 + .1) * (2 + .1) - 5 * 2 = .1 * 2 + .1 * 5 = .7 cm^2
Then you report A = 10 cm^2 +- .7 cm^2 including the - sign for completeness
Answer:
When you moved the compass near a bar magnet, the needle pointed toward the magnet's magnetic field and not toward the north.
Explanation:
When ANY pendulum bob reaches the top of its swing,
it stops momentarily and then begins to drop. At the instant
when it stops, its kinetic energy is zero.
