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Burka [1]
3 years ago
14

Two asteroids are 100,000 m apart. One has a mass of 3.5 x 106 kg. If the

Physics
2 answers:
max2010maxim [7]3 years ago
7 0

Answer:

mass of the other asteroid = 4.49*10^9kg\\

Explanation:

We use the definition for the force between two celestial objects under the action of the gravity they produce using newton's general gravitational constant: G=6.674*10^{-11} \frac{N*m^2}{kg^2}

The force between the two asteroids will then be given by:

F_G=G*\frac{M_1*M_2}{d^2}

where G is Newton's gravitational constant, the asterioid's masses are M1 and M2 respectively, and d is the distance between them.

We replace the known values in he equation above, and solve for the missing mass:

F_G=G*\frac{M_1*M_2}{d^2}\\1.05*10^{-4}N=6.674*10^{-11} \frac{N*m^2}{kg^2} \frac{3.5*10^6kg*M_2}{(10^5m)^2} \\1.05*10^{-4}=2.3359*10^{-14} * M_2\\M_2=\frac{1.05*10^{-4}}{2.3359*10^{-14}} =4.49*10^9kg

Since the units for the given quantities are all in the SI system, our resultant units for the unknown mass of the asteroid will be in kg.

hram777 [196]3 years ago
5 0

Answer:

4.5*10^9

Explanation:

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4 years ago
Certain neutron stars (extremely dense stars) are believed to be rotating at about 10 rev/s. If such a star has a radius of 18 k
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Answer:

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Explanation:

When the neutron star rotates rapidly, a material on its surface to remain in place, the magnitude of the gravitational acceleration on the central material must be equal to magnitude of the centripetal acc. of the rotating star.

That is

\frac{GM_{ns}}{R^2}= \omega^2 R

M_ns = mass odf the netron star.

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3 years ago
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