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3 years ago

Two asteroids are 100,000 m apart. One has a mass of 3.5 x 106 kg. If the

Physics

2 answers:

max2010maxim [7]3 years ago

7 0

Answer:

mass of the other asteroid = $4.49*10^9kg\\$

Explanation:

We use the definition for the force between two celestial objects under the action of the gravity they produce using newton's general gravitational constant: $G=6.674*10^{-11} \frac{N*m^2}{kg^2}$

The force between the two asteroids will then be given by:

$F_G=G*\frac{M_1*M_2}{d^2}$

where G is Newton's gravitational constant, the asterioid's masses are M1 and M2 respectively, and d is the distance between them.

We replace the known values in he equation above, and solve for the missing mass:

$F_G=G*\frac{M_1*M_2}{d^2}\\1.05*10^{-4}N=6.674*10^{-11} \frac{N*m^2}{kg^2} \frac{3.5*10^6kg*M_2}{(10^5m)^2} \\1.05*10^{-4}=2.3359*10^{-14} * M_2\\M_2=\frac{1.05*10^{-4}}{2.3359*10^{-14}} =4.49*10^9kg$

Since the units for the given quantities are all in the SI system, our resultant units for the unknown mass of the asteroid will be in kg.

hram777 [196]3 years ago

5 0

Answer:

4.5*10^9

Explanation:

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A woman exerts a horizontal force of 113 N on a crate with a mass of 31.2 kg.

sergeinik [125]

Answer:

a) 113N

b) 0.37

Explanation:

a) Using the Newton's second law:

\sum Fx =ma

Since the crate doesn't move (static), acceleration will be zero. The equation will become:

\sum Fx = 0

\sumFx = Fm - Ff = 0.

Fm is the applied force

Ff is the frictional force

Since Fm - Ff = 0

Fm = Ff

This means that the applied force is equal to the force of friction if the crate is static.

Since applied force is 113N, hence the magnitude of the static friction force will also be 113N

b) Using the formula

Ff = nR

n is the coefficient of friction

R is the reaction = mg

R = 31.2 × 9.8

R = 305.76N

From the formula

n = Ff/R

n = 113/305.76

n = 0.37

Hence the minimum possible value of the coefficient of static friction between the crate and the floor is 0.37

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2 years ago

2. What is the feather's initial velocity (before it is dropped) in m/s?

Dmitrij [34]

Answer: 0

Explanation: Initial velocity is 0.

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2 years ago

What is formed from at least two types of chemically combined atoms?

SashulF [63]

A compound. For example, hydrogen and oxygen atoms form water.

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2 years ago

What are the seven different forms of energy? Give an example of each.

wel

Answer:

Form of energy: Example

1. Light energy: Electromagnetic radiation

2. Nuclear energy: Nuclear fission

3. Chemical energy: Energy stored in plant matter

4. Electrical energy: Lightning

5. Thermal energy: A hot surface

6. Sound energy: A tuning fork

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3 years ago

An object of mass m = 5.0 kg hangs from a cord around a light pulley: The length of the cord between the oscillator and the pull

puteri [66]

Answer:

$\mu=0.0049Kg/m$

Explanation:

When a standing wave is formed with six loops means the normal mode of the wave is n=6, the frequency of the normal mode is given by the expression:

$f_n=\frac{nv}{2L}$

Where $L$ is the length of the string and $v$ the velocity of propagation. Use this expression to find the value of $v$ .

$f_6=\frac{6v}{2L}\\(150)=\frac{6v}{2(2)} \\150=\frac{3v}{2} \\3v=150(2)\\ v=\frac{300}{3} \\v=100m/s$

The velocity of propagation is given by the expression:

$v=\sqrt{\frac{T}{\mu }$

Where $\mu$ is the desirable variable of the problem, the linear mass density, and $T$ is the tension of the cord. The tension is equal to the weight of the mass hanging from the cord:

$T=W=mg=(5)(9.81)=49.05N$

With the value of the tension and the velocity you can find the mass density:

$v=\sqrt{\frac{T}{\mu}$

$v^2=\frac{T}{\mu}\\ \mu=\frac{T}{v^2} =\frac{49.05}{(100)^2} =\frac{49.05}{10000} =0.0049Kg/m$

6 0

2 years ago