Explanation:
The attached figure shows the position-time graph of a ladybug. We need to find the average speed of the ladybug between t = 4 s to t = 7 s.
We know that, the slope of a position-time graph gives velocity of an object. It can be given by :

In this case, the position of a ladybug at t = 4 s and at t = 7 s is the same i.e. 2 m.
It means its velocity is equal to at this time or we can say that ladybug is at rest.
No, there isn't. Please consult your doctor if this is the case with yours or someone you know.
Answer:
Work done = Force X Distance
Work done/Force = Distance
2700/560 = Distance
Distance = 4.8 meters
Answer:
given,
children on left shore pulls the rope by 3 N
Children on the right shore pulls the rope by 2 N
speed of the box = 3 m/s
a) Power = Force x Velocity
Power = 3.0 N * 3
Power = 9 Watt
Power = 2.0 N x 3
Power = 6 Watt
b) Net Force = 3.0 N - 2.0 N = 1.0 N
Net Power = 1.0 x 3 Watt
Net Power = 3 Watt
c) net force is acting on the box and at an instant velocity is given so, when the body moves it will accelerate and velocity will change so, the value of part A and B will also change