Answer:
b . Move the conductor near a magnet
To the right, if you push something left the friction is to the right
(a) 3.5 Hz
The angular frequency in a spring-mass system is given by

where
k is the spring constant
m is the mass
Here in this problem we have
k = 160 N/m
m = 0.340 kg
So the angular frequency is

And the frequency of the motion instead is given by:

(b) 0.021 m
The block is oscillating up and down together with the upper end of the spring. The block will lose contact with the spring when the direction of motion of the spring changes: this occurs when the spring is at maximum displacement, so at
x = A
where A is the amplitude of the motion.
The maximum displacement is given by Hook's law:

where
F is the force applied initially to the spring, so it is equal to the weight of the block:

k = 160 N/m is the spring constant
Solving for A, we find

<h2>
The secondary voltage is 115 V.</h2>
Explanation:
The primary to secondary voltage ratio is given as 4:1 .
That is

We need to find what is the secondary voltage if the primary voltage is 460 volts.
That is

Substituting in ratio equation

The secondary voltage is 115 V.