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Lapatulllka [165]
4 years ago
9

Please someone help me lol

Physics
1 answer:
Makovka662 [10]4 years ago
7 0
From Largest to Smallest:

Earth > Biosphere > Biome > Ecosystem > Community > Population > Organism > Organelles 

Hope this helps!

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The modern periodic law, according to Moseley, classifies elements based on arranging elements in ___ order
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D because it makes sense
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Which of the following actions will induce an emf in a conductor?
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b . Move the conductor near a magnet

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If you are pushing an object to the left, which way is the friction force acting?
AleksandrR [38]
To the right, if you push something left the friction is to the right


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A vertical spring (spring constant =160 N/m) is mounted on the floor. A 0.340-kg block is placed on top of the spring and pushed
AleksandrR [38]

(a) 3.5 Hz

The angular frequency in a spring-mass system is given by

\omega=\sqrt{\frac{k}{m}}

where

k is the spring constant

m is the mass

Here in this problem we have

k = 160 N/m

m = 0.340 kg

So the angular frequency is

\omega=\sqrt{\frac{160 N/m}{0.340 kg}}=21.7 rad/s

And the frequency of the motion instead is given by:

f=\frac{\omega}{2\pi}=\frac{21.7 rad/s}{2\pi}=3.5 Hz

(b) 0.021 m

The block is oscillating up and down together with the upper end of the spring. The block will lose contact with the spring when the direction of motion of the spring changes: this occurs when the spring is at maximum displacement, so at

x = A

where A is the amplitude of the motion.

The maximum displacement is given by Hook's law:

F=kA

where

F is the force applied initially to the spring, so it is equal to the weight of the block:

F=mg=(0.340 kg)(9.81 m/s^2)=3.34 N

k = 160 N/m is the spring constant

Solving for A, we find

A=\frac{F}{k}=\frac{3.34 N}{160 N/m}=0.021 m

3 0
3 years ago
If the primary to secondary voltage ratio is 4:1 for a transformer, what is the secondary voltage if the primary voltage is 460
Vesnalui [34]
<h2>The secondary voltage is 115 V.</h2>

Explanation:

The primary to secondary voltage ratio is given as 4:1 .

That is

                 \frac{V_p}{V_s}=\frac{4}{1}=4

We need to find what is the secondary voltage if the primary voltage is 460 volts.

That is

                    V_p=460V

Substituting in ratio equation

                    \frac{V_p}{V_s}=4\\\\\frac{460}{V_s}=4\\\\V_s=\frac{460}{4}\\\\V_s=115V

The secondary voltage is 115 V.                  

6 0
3 years ago
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