C → A → E → D → F → H → G → I → B
Explanation:
Put into the proper order, the following are the stages of star formation from earliest to latest:
Massive, rotating, amorphous interstellar cloud collapses and fragments → Infalling material forms a hot and luminous protostar at the center of the disk → Gravitational contraction causes protostar to shrink and heat as it descends the Hyashi track → As the shrinking protostar heats up, hydrogen is ionized and a magnetic field forms → Magnetic bipolar outflows begin along rotation axis as the magnetic field forms → As bipolar outflows become stronger, powerful T-Tauri winds start clearing the nebula before the onset of nuclear fusion → Shrinking cloud collapses into a flat disk shape → Onset of nuclear fusion in the core occurs around 15 million K → Newly-formed star settles onto the Main Sequence
Answer:
The electric charge, q (in coulomb units) = 5004 C
Given:
The charge stored as printed on NiMH battery, q = 1390 mAh
Solution:
To express the amount of electric charge printed on the battery in milli-ampere-hour (mAh) in coulomb, we will do simple conversion of milli amperes in ampere and hours in seconds:
1 mA = 
1 hour = 
Also, we know that the rate of flow of charge is electric current, I:
I = 
⇒ q = [tex]I\times t[tex] (1)
where
q = electric charge
I = current
t = time taken for flow of current
Using eqn(1), we get:
q = [tex]1390\times 10^{-3}\times 60\times 60[tex]
q = 5004 A-s = 5004 C
Answer:
Explanation:
A )
When empty , H₀ length of barge is inside water .
volume of barge inside water = A x H₀
Weight of displaced water = AH₀ x ρ x g
Buoyant force = weight of displaced water = AH₀ ρg
B)
It should balance the weight of barge
Weight = buoyant force
Weight = AH₀ ρg
mass of barge = weight / g
weight / g = AH₀ ρ
= 550 x .55 x 1000
= 302500 kg
Answer:
q = 0.384 C
Explanation:
The total charge present at the head can be easily found out by multiplying the charge on a single electron with the total number of electrons present on the head:

where,
q = total charge on head = ?
n = total no. of electrons on the head = 2.4 x 10¹⁸
e = charge on 1 electron = 1.6 x 10⁻¹⁹ C
Therefore,

<u>q = 0.384 C</u>