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ladessa [460]
3 years ago
15

What is the percent composition of Fluorine in CF5?

Chemistry
1 answer:
posledela3 years ago
6 0
The answer is 100%
let me know if you want an explanation
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If you are given only the mass number of neutrons, how do we find an atomic number?
77julia77 [94]

Mass number is the sum of protons and neutrons.

Atomic number is the total number of protons present.

Mass number = protons + neutrons

Atomic number = protons present.

From the above equations we can conclude that,

Atomic number= Mass number- neutrons.

Thus we can find out the atomic number by subtracting the number of neutrons from the mass number.

3 0
3 years ago
Read 2 more answers
Anyone know the answer
kodGreya [7K]

Answer:

a and d

Explanation:

a bromine and the calcium atom loses two elections

6 0
3 years ago
Which letter shows the most direct sunlight?
timama [110]

Answer:c

Explanation:because the light is hitting the Earth straight on without a slant or without all the light, it is the most direct

6 0
3 years ago
What is the oxidizing agent in the reaction 2MnO4-(aq) 10I-(aq) 16H (aq) ---> 2Mn2 (aq) 5I2(aq) 8H2O(l)
faltersainse [42]

Correct Question: what is the oxidizing agent in the reaction.

2MnO4–(aq) +10Cl–(aq) + 16H+(aq) --------> 5Cl2(g) + 2Mn2+(aq) +8H2O(l)

Answer: MnO4-is the oxidizing agent

Explanation:

In the reaction 2MnO4–(aq) +10Cl–(aq) + 16H+(aq) --------> 5Cl2(g) + 2Mn2+(aq) +8H2O(l)

Oxidizing agent oxidizes other molecules while the themselves get reduced.

oxidizing agents give away Oxygen to other compounds.

MnO4-is the oxidizing agent because

On the reactants side

Oxidation number of Mn in 2MnO4- is +7

Oxidation number of Cl- is -1

On the products side

Oxidation number of Mn is +2

While oxidation number of Cl is zero

Therefore the oxidizing agent is 2MnO4 because is oxidizes Chlorine from -1 to 0 while itself got reduced from oxidation state of +7 to +2

4 0
3 years ago
When the oxidation number of an element decreases over the course of a reaction, that element has beenWhich of the following che
NARA [144]
AgNO3+NaCl yields AgCl+NaNo3 (reduction)
...that's the only one I know
4 0
3 years ago
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