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ladessa [460]
3 years ago
15

What is the percent composition of Fluorine in CF5?

Chemistry
1 answer:
posledela3 years ago
6 0
The answer is 100%
let me know if you want an explanation
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ANSWER ASAP
Ugo [173]
The numbers inside the boxes represent the atomic number. the circles and dots represent the shells and electrons.
4 0
3 years ago
Read 2 more answers
Carbon diselenide (CSe2) is a liquid at room temperature. The normal boiling point is 125°C, and the melting point is –45.5°C. C
Tema [17]

Answer:

Explanation:  The strengths of the inter molecular forces varies as follows -

        CO_{2}< CS_{2} < CSe_{2}

The normal boiling point of CSe2 is 125°C and that of CS2 is 116°C, which explains the trend that as we move down the group, the boiling point of e compound increases as the size increases.

This usually happens because larger and heavier atoms have a tendency to exhibit greater inter molecular strengths due to the increase in size . As the size increases, the valence shell electrons move far away from the nucleus, thus has a greater tendency to attract the temporary dipoles.

And larger the inter molecular forces, more tightly the electrons will be held to each other and thus more thermal energy would be required to break the bonds between them.

5 0
3 years ago
3NO2(g) + H2O(l) — 2HNO3(aq) + NO(g)
antiseptic1488 [7]

Answer:

A. 3.65 g of H2O.

B. 26.33 g of NO.

C. 7.53 g of HNO3.

Explanation:

The balanced equation for the reaction is given below:

3NO2(g) + H2O(l) —> 2HNO3(aq) + NO(g)

Next, we shall determine the masses of NO2 and H2O that reacted and the masses of HNO3 and NO produced from the balanced equation.

This is illustrated below:

Molar mass of NO2 = 14 + (16x2) = 46 g/mol

Mass of NO2 from the balanced equation = 3 x 46 = 138 g

Molar mass of H2O = (2x1) + 16 = 18 g/mol

Mass of H2O from the balanced equation = 1 x 18 = 18 g

Molar mass of HNO3 = 1 + 14 + (16x3) = 63 g/mol

Mass of HNO3 from the balanced equation = 2 x 63 = 126 g.

Molar mass of NO = 14 + 16 = 30 g/mol

Mass of NO from the balanced equation = 1 x 30 = 30 g.

Summary:

From the balanced equation above,

138g of NO2 reacted with 18 g of H2O to produce 126 g of HNO3 and 30 g of NO.

A. Determination of the mass of H2O required to react with 28.0 g

of NO2.

This is illustrated below:

From the balanced equation above,

138g of NO2 reacted with 18 g of H2O.

Therefore, 28 g if NO2 will react with = (28 x 18)/138 = 3.65 g of H2O.

Therefore, 3.65 g of H2O is needed for the reaction.

B. Determination of the mass of NO produced from 15.8 g of H2O.

This is illustrated below:

From the balanced equation above,

18 g of H2O reacted to produce 30 g of NO.

Therefore, 15.8 g of H2O will react to produce = (15.8 x 30)/18 = 26.33 g of NO.

Therefore, 26.33 g of NO were produced from the reaction.

C. Determination of the mass of HNO3 produced from 8.25 g of NO2.

This is illustrated below:

From the balanced equation above,

138g of NO2 reacted to produce 126 g of HNO3.

Therefore, 8.25 g of NO2 will react to produce = (8.25 x 126)/138 = 7.53 g of HNO3.

Therefore, 7.53 g of HNO3 were produced from the reaction.

7 0
3 years ago
This pluton occurs deep in Earth and does not cause any changes to the surface of Earth . True or False
irakobra [83]

Answer:

The given statement is false.

Explanation:

  • However, if the pluton exists beneath the ground, this could be conveniently shown in the illustration something from the peak such pluton appears convex in form resembling a lopolith and perhaps diapir, which would be a particular form of statistically significant pluton recognized as the sill.
  • Mostly from the figure it could also be shown that subsurface sheets are lined or curved, throughout the pluton mold. And therefore it is inferred that such a pluton creates adjustment to something like the ground atmosphere by altering the form of the levels above it.

So that the given is incorrect.

7 0
3 years ago
The hypothetical elements shown here (figures a–d) do not include hydrogen or helium. Which element would you expect to bond cov
Marizza181 [45]
The answer is "Figure a" i did it on plato lol
4 0
3 years ago
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