Answer:
The energy released will be -94.56 kJ or -94.6 kJ.
Explanation:
The molar mass of methane is 16g/mol
The given reaction is:

the enthalpy of reaction is given as ΔH = -890.0 kJ
This means that when one mole of methane undergoes combustion it gives this much of energy.
Now as given that the amount of methane combusted = 1.70g
The energy released will be:

The answer is 4 hope that help.
Answer:
Trial Number of moles
1 0.001249mol
2 0.001232mol
3 0.001187 mol
Explanation:
To calculate the <em>number of moles of tritant</em> you need its<em> molarity</em>.
Since the<em> molarity</em> is not reported, I will use 0.1000M (four significant figures), which is used in other similar problems.
<em>Molarity</em> is the concentration of the solution in number of moles of solute per liter of solution.
In this case the solute is <em>NaOH</em>.
The formula is:

Solve for the <em>number of moles:</em>

Then, using the molarity of 0.1000M and the volumes for each trial you can calculate the number of moles of tritant.
Trial mL liters Number of moles
1 12.49 0.01249 0.01249liters × 0.1000M = 0.001249mol
2 12.32 0.01232 0.01232liters × 0.1000M = 0.001232mol
3 11.87 0.01187 0.01187liters × 0.1000M = 0.001187 mol
In a heterogeneous mixture the materials are mixed together and will be easily separated. The correct option among all the options that are given in the question is the second option or option "b". An example of a heterogeneous mixture is a bowl of colored candies. I hope the answer helps you.
Hey there!
We balance chemical equations because of the law of conservation of mass.
The law of conservation of mass states that matter cannot be created or destroyed, so we must have the same amount of each element on each side of a chemical equation.
The products of a chemical reaction must be equal to the reactants to follow the law of conservation of mass.
Hope this helps!