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salantis [7]
3 years ago
12

CH3(CH2)50CH3 How many atoms

Chemistry
1 answer:
ahrayia [7]3 years ago
3 0

24

Explanation:

An atom is the smallest indivisible particle of any matter. Atoms are distinct and distinguishable from one another and are called elements:

                             CH₃(CH₂)₅0CH₃

 There are 3 different kinds of atoms in the compound above called  

elements

                               Carbon

                               Hydrogen

                               Oxygen

 In the compound the subscripts gives the number of atoms:

                                C - 7

                                H - 16

                                0 - 1

    Number of atoms in the compound is 24.

Learn more:

Number of atoms brainly.com/question/10419836

#learnwithBrainly

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Black_prince [1.1K]

Answer:

The correct option is: A) 2H₂(g) + O₂(g) → 2H₂O(g)

Explanation:

According to the Le Chatelier's principle, change in the volume of the reaction system causes equilibrium to shift in the direction that reduces the effect of the volume change.

When the <u>volume decreases then the pressure of the reaction vessel increases, then the equilibrium shifts towards the reaction side that produces less number of moles of gas.</u>

<u />

A) 2H₂(g) + O₂(g) → 2H₂O(g)

The number of moles of reactant is 3 and number of moles of product is 2.

<u>Therefore, when volume decreases, the equilibrium shifts towards the product side, thereby </u><em><u>favoring the formation of products.</u></em>

B) NO₂(g) + CO(g) → NO(g) + CO₂(g)

The number of moles of reactant and product both is 2.

<u>Therefore, when the volume decreases, the equilibrium does not shift in any direction.</u>

C) H₂(g) + I₂(g) → 2HI(g)

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<u>Therefore, when the volume decreases, the equilibrium does not shift in any direction.</u>

D) 2O₃(g) → 3O₂(g)

The number of moles of reactant is 2 and number of moles of product is 3.

<u>Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby </u><em><u>favoring the formation of reactants.</u></em>

E) MgCO₃(s) → MgO(s) + CO₂(g)

The number of moles of reactant is 1 and number of moles of product is 2.

<u>Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby </u><em><u>favoring the formation of reactants.</u></em>

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