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Luda [366]
3 years ago
5

mc015-1.jpg has coordinates of A(–6, –7), B(4, –2), and C(0, 7). Find the coordinates of its image after a dilation centered at

the origin with a scale factor of 2
Mathematics
1 answer:
Tasya [4]3 years ago
4 0
A (-12, -14)
B (8, -4)
C(0, 14)
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Analyze the key features of the graph f(x) = 1/x+3 -2
tia_tia [17]
<h2>Explanation:</h2><h2></h2>

Here we have the following rational function:

f(x) = \frac{1}{x+3} -2

So the graph of this function is shown in the First Figure below. Let's define another function which is a parent function:

g(x)=\frac{1}{x}

Whose graph is shown in the second figure below. So we can get the graph of f from the graph of g this way:

Step 1. Shift the graph 3 units to the left:

f_{1}(x) = \frac{1}{x+3}

Step 2. Shift the graph 2 units down:

f(x) = \frac{1}{x+3}-2

Finally, the features of the graph of f are:

The graph of this function comes from the parent function g and the transformations are:

  • A shifting 3 units to the left
  • A shifting 2 units down

8 0
2 years ago
Need help with this khan academy question. Plus minus square root of negative nine equals plus or minus
klemol [59]

Answer:

3i

Step-by-step explanation:

3i x 3i = -9

-3i x -3i = -9

Therefore the square root of -9 is 3i or -3i

3 0
3 years ago
The sum of 3 consecutive numbers are 24. What are the numbers? Please explain.
victus00 [196]
Consecutive numbers mean in order from smallest to largest, therefore, 7, 8, 9, would be the answer. 7+8+9=24.
4 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!
natima [27]
Expression: 3⁴ . 2³

= 3 * 3 * 3 * 3 * 2 * 2 * 2

= 81 * 8

= 648

In short, Your Answer would be: 648

Hope this helps!
3 0
3 years ago
Read 2 more answers
Consider the initial value problem 2ty′=4y, y(2)=−8. 2ty′=4y, y(2)=−8. find the value of the constant cc and the exponent rr so
Softa [21]
2ty'=4y
Replacing y'=dy/dt in the equation:
2t(dy/dt)=4y
Grouping terms:
dy/y=4dt/(2t)
dy/y=2dt/t
Integrating both sides:
ln(y)=2ln(t)+ln(c), where c is a constant
Using property logarithm:  b ln(a) = ln(a^b), with b=2 and a=t
ln(y)=ln(t^2)+ln(c)
Using property of logarithm: ln(a)+ln(b) = ln(ab), with a=t^2 and b=c
ln(y)=ln(ct^2)
Then:
y=ct^2
Using the initial condition: y(2)=-8
t=2→y=-8→c(2)^2=-8→c(4)=-8
Solving for c:
c=-8/4
c=-2

Then the solution is y=-2t^2
Comparing with the solution: y=ct^r
c=-2, r=2

Answer: T<span>he value of the constant c is -2 (c=-2) and the exponent r is 2 (r=2)</span>
 
5 0
3 years ago
Read 2 more answers
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