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never [62]
3 years ago
11

Igneous rock___to form magma a)melts b)weathers c)compacts d)crystallizes NEED HELP ASAP

Chemistry
2 answers:
dangina [55]3 years ago
5 0

Answer:

should be A)Melts.Because magma is liquid i think

andrew11 [14]3 years ago
3 0

Answer:

a) melt to form magma

Explanation:

because in my science class.  I learned the cycle that igneous rock in form from volcano and it melts into magma

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Suppose a solution is prepared by dissolving 15.0 g NaOH in 0.150 L of 0.250 M nitric acid. What is the final concentration of O
Kipish [7]

Answer:

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

Explanation:

Moles of NaOH = \frac{15.0 g}{40 g/mol}=0.375 mol

Molarity of the nitric acid solution = 0.250 M

Volume of the nitric solution = 0.150 L

Moles of nitric acid = n

Molarity=\frac{Moles}{Volume(L)}

n=0.250 M\times 0.150 L=0.0375 mol

NaOH+HNO_3\rightarrow NaNO_3+H_2O

According to reaction, 1 mole of nitric acid recats with 1 mole of NaOH, then 0.0375 moles of nitric acid will react with :

\frac{1}{1}\times 0.0375 mol of NaOH

Moles of NaOH left unreacted  in the solution =

= 0.375 mol - 0.0375 mol = 0.3375 mol

NaOH(aq)\rightarrow Na^+(aq)+OH^-(aq)

1 mole of sodium hydroxide gives 1 mol of sodium ions and 1 mole of hydroxide ions.

Then 0.3375 moles of NaOH will give :

1\times 0.3375 moles=0.3375 mol of hydroxide ion

The molarity of hydroxide ion in solution ;

=\frac{0.3375 mol}{0.150 L}=2.25 M

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

3 0
3 years ago
Determine the maximum amount of Fe that was produced during the experiment. Explain how you determined this amount.
dsp73

Answer:

5 moles of Fe

Explanation:

The equation of the reaction is;

2 Al(s) + Fe 2O 3(s) --> 2Fe (s) + Al 2O 3 (s)

Now;

1 mole of Fe2O3 require 2 moles of Al

3 moles of Fe2O3 requires 3 × 2/1 = 6 moles of Al

Hence Al is the limiting reactant.

If 2 moles of Al yields 2 moles of Fe

5 moles of Al yields 5 × 2/2 = 5 moles of Fe

5 0
2 years ago
How many moles of S are in 35.4 g of (C3H5)2S?
alexandr402 [8]
<span>0.310 moles First, look up the atomic weights of the elements involved. Atomic weight carbon = 12.0107 Atomic weight hydrogen = 1.00794 Atomic weight sulfur = 32.065 Molar mass (C3H5)2S = 6 * 12.0107 + 10 * 1.00794 + 32.065 = 114.2086 g/mol Moles (C3H5)2S = 35.4 g / 114.2086 g/mol = 0.309959145 mol Since there's just one sulfur atom per (C3H5)2S molecule, the number of moles of sulfur will match the number of moles of (C3H5)2S which is 0.310 when rounded to 3 significant digits.</span>
6 0
3 years ago
Of the elements calcium, Ca, beryllium, Be, barium, Ba, and strontium, Sr, which has the largest atomic radius? Explain your ans
Nezavi [6.7K]
The largest atomic radius has Ba,because they are all metals of 2nd group,but as you know when you go down upright in the periodic table the metallic features getting stronger but also orbital layers increasing,and you can say more layers larger atomic radius.Hope I helped,sorry for English
8 0
3 years ago
Read 2 more answers
(Link; https://www.chemteam.info/SigFigs/SigFigsFable.html)
Anna007 [38]

1. The measurement turned out to be so expensive since the student did not rely on the significant figures to calculate the edge of the cube and approximate it to the next value (2.1 cm possibly) that would allow a simpler construction and therefore its cost was much lower .

2. The student had to take all the significant figures in his calculations, with which he would have:

Volume = \frac{mass}{density}

Volume = \frac{80g}{8.67g/mL}

Volume = 9.2272203 mL

Since the figure to be constructed is a cube, he had to calculate the cube root of the volume to find the value of the edge of the cube:

Edge of the cube = \sqrt[3]{9.2272203 cm^{3} } (Taking into account that cm^{3} is proportional to mL)

Edge of the cube = 2.097443624 cm

Because the cube edge value is so specific, in order to manage his budget, he was able to order a 2.1 cm cube, which would bring the mass up to 80.29287 g, and in the lab reduce one of the faces to the appropriate weight. .

On the other hand, the main thing he had to do was ask how much it would cost to make a cube with those specifications, especially when they mentioned that it would be "expensive" and he only had $50.

The significant figures guarantee the correct operation of a machinery, a gear, a team in general, for which the accuracy will not only be taken to the millimeter, but sometimes microns or much more specific, as in the case of computer components, Therefore, it is very important, if not, and if arbitrary measurements are taken that do not consider significant figures, the components could not function properly, which would cause a loss in time, effort and manpower.

If you want to learn more about exercises with significant figures, you can see the next link: brainly.com/question/11904364?referrer=searchResults

4 0
2 years ago
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