C₄H₉OH + HBr = C₄H₉Br + H2O
Δmole of alcohol gives 1 mole of bromobutanol
HBr is in excess, so the yield of the product is limited by the alcohol
Wt. of 1 butanol = 18
Molar mass of the butanol = 74.12 g/mole
Moles of the alcohol = 1/74.12 = 0.01349 moles
So, moles of bromobutane = 0.01349 moles
Molar mass of C₄H₉Br = 137.018 g/moles
So, theoretical mass of bromobutane is = 0.01349 × 137.0.18
= 1.85 g
You just need the number of protons and number of neutrons as the mass of eelctrons is negligible
Answer: 151 kJ
Explanation:
To calculate the moles :
It is given that:
0.267 moles of 
absorb energy = 40.3 kJ
Thus 1 mole of absorb energy =
Thus the value of 
for the chemical equation given is 151 kJ
Answer:
3.727x10^24 atoms.
Explanation:
When calculating how many molecules are in a compound or element, we refer to Avogardo's number.
Your equation will look like this: 1 mole/ 6.022x10^23 molecules (Avogardo's number).
Multiply 6.19 by Avogardo's number to get your answer.
