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Sergeu [11.5K]
3 years ago
8

4. Which of the following aromatic compounds undergoes nitration faster than benzene does? Explain your answer

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer:

Ph-OH

Explanation:

Nitration of Aromatic compounds is an example for Aromatic Electrophilic substitution and its rate is enhanced by Electron donating group like OMe, OH, alkyl group and halides (least activating group) while reactivity is diminished by electron withdrawing like CN,NO2 and Ketone etc

Hence phenol is more reactive than benzene towards nitration.

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Artyom0805 [142]
Not necessarily, rain needs some mechanism such as instability of vertical air movement..
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Sugar is dissolved in water. Which is the solute? sugar neither both water
lina2011 [118]

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Explanation:

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You are a chemist working in your laboratory. In your storage closet you have a
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Ans is B.Bromine. Only two elements are liquid at room temperature ( mercury and Bromine) . Helium and chlorine, arsenic are gases.
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3 years ago
How many molecules of co2 in 97.3 grams of co2
s2008m [1.1K]

Answer:

1.33 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

  • Reading a Periodic Table
  • Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

97.3 g CO₂

<u>Step 2: Define conversions</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

97.3 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.33138 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

1.33138 × 10²⁴ molecules CO₂ ≈ 1.33 × 10²⁴ molecules CO₂

8 0
3 years ago
calculate the atomic mass of carbon if the two common isotopes of carbon have masses of 12.000 amu (98.89% abundance) and 13.003
Bingel [31]

12.01 amu

Work:

(12.000 × .9889) + (13.003 × .0111) = 12.01

  • turn the precents into decimals

6 0
3 years ago
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