A certain material has a mass of 241.25 g while occupying 12.5 cm3 of space. what is this material? (hint: use table 3.1).
1 answer:
To get the density of the material, the formula would be: mass divided by volume which is denoted by d = m/v
So for this problem, the mass is 241.25 g and the volume is 12.5 cm^3
so plugging in the data, we have: d = 241.25 g / 12.5 cm^3 = 19.3 g/cm^3
The answer is Tungsten, you could see it in the table, in the attached file.
So for this problem, the mass is 241.25 g and the volume is 12.5 cm^3
so plugging in the data, we have: d = 241.25 g / 12.5 cm^3 = 19.3 g/cm^3
The answer is Tungsten, you could see it in the table, in the attached file.
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Answer: 0.1161 grams of mercury(II) sulfide) form.
Explanation:
To calculate the number of moles for given molarity, we use the equation:
.....(1)
a) Molarity of solution = 0.10 M
Volume of solution = 0.020 L
Putting values in equation 1, we get:
b) Molarity of solution = 0.010 M
Volume of solution = 0.050 L
Putting values in equation 1, we get:
According to stoichiometry :
1 mole of reacts with 1 mole of
Thus 0.0005 moles of reacts with=
moles of
Thus is the limiting reagent and
is the excess reagent.
According to stoichiometry :
1 mole of forms= 1 mole of
Thus 0.0005 moles of forms=
moles of
mass of
Thus 0.1161 grams of mercury(II) sulfide) form.