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bazaltina [42]
3 years ago
8

A certain material has a mass of 241.25 g while occupying 12.5 cm3 of space. what is this material? (hint: use table 3.1).

Chemistry
1 answer:
andre [41]3 years ago
4 0
To get the density of the material, the formula would be: mass divided by volume which is denoted by d = m/v
So for this problem, the mass is 241.25 g and the volume is 12.5 cm^3
so plugging in the data, we have: d = 241.25 g / 12.5 cm^3 = 19.3 g/cm^3

The answer is Tungsten, you could see it in the table, in the attached file.

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3 years ago
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Just need this answered i understand it just need to study for something else
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The silver nitrate in 20.00 mL of a certain solution was allowed to react with sodium chloride according to the following equati
valentinak56 [21]

Answer:

The answer to your question is: 0.1 M

Explanation:

data

Volume of AgNO3 = 20.00 ml

                   1000 ml --------------  1 l

                       20 ml --------------- x              

          x = 20x 1 /1000 = 0.02

AgCl = 0.2867 g

MW of AgCl = 35.45 + 107.9 = 143.35 g

                       143.35 g -------------- 1 mol

                       0.2867 g -------------  x

  x = 0.2867 x 1 / 143.35 = 0.002 moles of AgCl

   From the balance reaction we see that the proportion of AgNO3 to AgCl is 1:1, then

           1 mol of AgNO3 -------------------- 1 mol of AgCL

                 x                   ---------------------  0.002 moles of AgCl

 x = 0.002 moles of AgNO3

   This moles of AgNO3 are in 20 ml or 0.02 liters

So, Molarity = # moles/liter

      Molarity = 0.002 moles/ 0.02 = 0.1 M

4 0
3 years ago
A gas occupies 1.00cm^3 at STP. What volume does it occupy at 710.0 mm Hg and 55.0°C
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Answer:

Final volume is 1.29cm³

Explanation:

Using combined gas law:

P₁V₁/T₁ = P₂V₂/T₂

<em>Where P is pressure, V volume and T absolute temperature of 1, initial state and 2, final state of a gas.</em>

<em />

We can solve the volume of the gas:

P₁ = 1atm at STP

V₁ = 1cm³

T₁ = 273.15K at STP

P₂ = 710mmHg * (1atm / 760mmHg) = 0.9342atm

V₂ = ?

T₂ = 55.0°C + 273.15K = 328.15K

Replacing:

1atm*1cm³/273.15K = 0.9342atm*V₂/328.15K

1.29cm³ = V₂

<h3>Final volume is 1.29cm³</h3>

<em />

6 0
2 years ago
If the temperature of the earth's layers increases by about 90 degrees fahrenheit for every 1 mile from the surface and you are
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The rate of change of the temperature of the Earth's surface is given to,
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To determine the temperature x miles away from the surface, we multiply the depth by the given rate. This will give us the answer of,
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Thus, the temperature 90 miles deep in the Earth's surface is equal to 8100°F. 
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