Fine the volume in dm³ and in Ml of a 0.505 mol/dm of NaCH required to react with 40Ml of 0.505 molar concentration of H2SO4

What is the main factor in the net driving force for filtration in the glomerulus?

Blizzard [7]

The main driving force for the filtering process, or outward pressure is the blood pressure as it enters the glomerulus.

4 0

3 years ago

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Sodium hydrogen carbonate , also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid ind

Yanka [14]

Answer:

The mass of NaHCO3 that she would need to ingest to neutralize this much HCl is 1.512g

Explanation:

The question can be better presented as follows:

Sodium hydrogen carbonate NaHCO3, also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid HCl, which the stomach secretes to help digest food. Drinking a glass of water containing dissolved NaHCO3 neutralizes excess HCl through this reaction: HCl(aq)+NaHCO3(aq)→NaCl(aq)+H2O(l)+CO2(g)

The CO2 gas produced is what makes you burp after drinking the solution. Suppose the fluid in the stomach of a woman suffering from indigestion can be considered to be 200.mL of a 0.089M HCl solution. What mass of NaHCO3 would she need to ingest to neutralize this much HCl? Be sure your answer has the correct number of significant digits.

SOLUTION

Given:

Volume of HCl = 200ml = 0.200L

Molarity of the HCl =>0.089M

The number of mole of HCl can be calculated using C=n/V

Therefore n = CxV = 0.089 × 0.2

=0.018 moles

Equation for the reaction:

HCl(aq)+NaHCO3(aq)→NaCl(aq)+H2O(l)+CO2(g)

From the equation, 1mole of HCl required 1mole of NaHCO3 for neutralization; therefore 0.018 moles of HCl will require 0.018 moles of NaHCO3.

But molar mass of NaHCO3 = 23+1+12+(16×3) = 84

Finally using number of moles = mass/molar mass

Therefore mass = 0.018 × 84

= 1.512g

8 0

3 years ago

Can someone please help me please

GaryK [48]

Liquids have more kinetic energy in their particles compared to solids. this allows the particles to move more freely, hence why they are fluids

Liquids diffuse from a region of high concentration to a region of low concentration, until equilibrium is reached

When heat is applied the particles gain more kinetic energy so they now have enough energy to overcome the bonds holding them in the liquid. this means they can evaporate off

8 0

3 years ago

How many grams are there in 3.4 x 10^24 atoms of He?

Lelechka [254]

Given :

Number of He atoms, $n = 3.4\times 10^{24}$ atoms.

To Find :

How many grams are their in given number of He atoms.

Solution :

We know, molecular mass of He is 4 g. It means that their are $6.022 \times 10^{23}$ atoms in 4 g of He.

Let, number of gram He in $3.4\times 10^{24}$ atoms is x , so :

$x = \dfrac{3.4\times 10^{24}}{6.022\times 10^{23}}\times 4\\\\x = $$22.58\ g$

Therefore, grams of He atoms is 22.58 g .

5 0

3 years ago

When a 5.00-g metal piece, A, was immersed in 38.0 mL of water, the water level rose to 50.0 mL. Similarly, when a 5.00-g metal

Mnenie [13.5K]

Answer:

A is denser than B as it's volume for the same mass is smaller.

Explanation:

Hello.

In this case, we first need to take into account that the density of each metal A and B is computed by dividing the mass over the volume of each metal which is actually computed by substracting the volume of water from the volume of the water and the solid:

$V_A=50.0mL-38.0mL=12.0mL\\\\V_B=60.0mL-38.0mL=22.0mL$

Next, we compute the densities as shown below:

$\rho_A=\frac{m_A}{V_A}=\frac{5.00g}{12.0mL}=0.42g/mL\\ \\\rho_B=\frac{m_B}{V_B}=\frac{5.00g}{22.0mL}=0.23g/mL$

In such a way, A is denser is B as it's volume for the same mass is smaller.

Best regards.

4 0

3 years ago

Fine the volume in dm³ and in Ml of a 0.505 mol/dm of NaCH required to react with 40Ml of 0.505 molar concentration of H2SO4​

Fine the volume in dm³ and in Ml of a 0.505 mol/dm of NaCH required to react with 40Ml of 0.505 molar concentration of H2SO4