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Advocard [28]
4 years ago
6

A student has two unopened 33 CL cans containing carbonated water. Can A has been stored in the garage 32 degrees and can B has

been stored in the fridge 8 degrees. The student opens one can at the time, both cans make a fizz.
A. Can A will make a louder and stronger fizz than can B.
B. Can B will make a louder and stronger fizz than can A
C. The fizz will be the same for both cans
D. There is not enough information to predict which can will make the louder fizz
Chemistry
1 answer:
IgorC [24]4 years ago
7 0

Answer:

A. Can A will make a louder and stronger fizz than can B.  

Explanation:

The solubility of a gas in a liquid decreases as the temperature increases, so the warmer can will have more undissolved carbon dioxide.

The warmer can will be under greater pressure, so it will make a louder and stronger fizz.

You might be interested in
9. Which of the following is true when we compare solids and gases?
djyliett [7]

Answer: b

Explanation:

8 0
3 years ago
(N2 &amp; O2 &amp; Ar &amp; CO2...) <br> an element compound or mixture?
ololo11 [35]

Answer: Mixture

Explanation:

Element is a pure substance which is composed of atoms of similar elements.

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.

Mixture is a substance which has two or more components which do not combine chemically and do not have any fixed ratio in which they are present. Example: Air which conatins a mixture of N_2, O_2 , Ar and CO_2

8 0
3 years ago
How many moles of water can be formed from 23.9 mol of oxygen gas?
ehidna [41]

Answer:

47.8 moles of H₂O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2H₂ + O₂ —> 2H₂O

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of H₂O

Finally, we shall determine the number of mole of water, H₂O, produced by the reaction of 23.9 moles of O₂. This can be obtained as follow:

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of H₂O.

Therefore, 23.9 moles of O₂ will react to produce = 23.9 × 2 = 47.8 moles of H₂O.

Thus, 47.8 moles of H₂O were obtained from the reaction.

3 0
3 years ago
50cm3 of a mixture of methane and hydrogen were mixed with excess oxygen and exploded, the product after cooling to the original
marin [14]

Answer:the initial composition of the reactants is

40cm^3 of CH4

40cm^3of H2

100cm^3 of H2O

Explanation:

Balanced reaction is

CH4 +H2+5/2O2______

CO2 +3H2O

Excess KOH at room temperature absorbs CO2 whose volume is given by 40cm^3 i.e the volume by which the solution decreases

So using Gay lussac combining ratio which states that gases combine in volumes that are in simple ratio to each other if gases.

Since CO2 in the equation is 1 mole

Means 1mole represent 40cm^3

So CH4:H2:O2 are in ratio of 1:1:5/2=(40:40:100)cm^3 respectively.

8 0
3 years ago
Is 2 C4H10 + 13 O2 → 8 CO2 + 10 H2O a double replacement?
natulia [17]

Answer:

The answer to your question is No, it is not.

Explanation:

Data

                C₄H₁₀  +  13O₂   ⇒   8CO₂ +  10H₂O

In a double replacement reaction, two reactants interchange cations an example of these reactions are neutralization reactions. In neutralization reactions, an acid and a base react to form a salt and water.

The reaction of this problem is not a double replacement reaction because the products are carbon dioxide and water, not a salt and water.

The reaction of this problem is a combustion reaction.

8 0
4 years ago
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