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Finger [1]
2 years ago
6

Weeks and how much money, in dollars, Jamal deposits into the savings account.

Chemistry
1 answer:
pantera1 [17]2 years ago
8 0

An

196 becase we all rice

Explanation:

You might be interested in
The chemical formula for sulfuric acid is H2SO4. In one molecule of sulfuric acid, there are _____.
erma4kov [3.2K]

Answer:

four atoms of oxygen

Explanation:

two atoms of hydrogen

one sulphur atom

5 0
3 years ago
Read 2 more answers
One gram of carbon contains 50,200,000,000,000,000,000,000 atoms. express the number of carbon atoms in scientific notation
german
N(C)=5,02·10²² atoms

calculation check:

N(C)=(1/12)*6.022*10²³=0.5018*10²³≈5.02·10²²
5 0
3 years ago
How man grams of cl2 are consumed to produce 12.0 g of KCl
Korvikt [17]

Answer:

5.71 g

Explanation:

Step 1: Write the balanced equation

2 K + Cl₂ ⇒ 2 KCl

Step 2: Calculate the moles corresponding to 12.0 g of KCl

The molar mass of KCl is 74.55 g/mol.

12.0 g × 1 mol/74.55 g = 0.161 mol

Step 3: Calculate the moles of Cl₂ needed to produce 0.161 moles of KCl

The molar ratio of Cl₂ to KCl is 1:2. The moles of Cl₂ needed are 1/2 × 0.161 mol = 0.0805 mol

Step 4: Calculate the mass corresponding to 0.0805 moles of Cl₂

The molar mass of Cl₂ is 70.91 g/mol.

0.0805 mol × 70.91 g/mol = 5.71 g

8 0
3 years ago
What is an acid<br>Define the term reactivity action<br>What is a compound​
valentinak56 [21]

Answer:

Acids are water-soluble and acidic chemical compounds, often expressed as the general formula HₓA.

6 0
3 years ago
Read 2 more answers
Under certain conditions, the equilibrium constant of the reaction below is Kc=1.7×10−3. If the reaction begins with a concentra
svetoff [14.1K]

Answer:

[Cl2] equilibrium = 0.0089 M

Explanation:

<u>Given:</u>

[SbCl5] = 0 M

[SbCl3] = [Cl2] = 0.0546 M

Kc = 1.7*10^-3

<u>To determine:</u>

The equilibrium concentration of Cl2

<u>Calculation:</u>

Set-up an ICE table for the given reaction:

               SbCl5(g)\rightleftharpoons SbCl3(g)+Cl2(g)

I                 0                    0.0546     0.0546

C              +x                        -x               -x

E               x                  (0.0546-x)    (0.0546-x)

Kc = \frac{[SbCl3][Cl2]}{[SbCl5]}\\\\1.7*10^{-3} =\frac{(0.0546-x)^{2} }{x} \\\\x = 0.0457 M

The equilibrium concentration of Cl2 is:

= 0.0546-x = 0.0546-0.0457 = 0.0089 M

5 0
3 years ago
Read 2 more answers
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