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MissTica
2 years ago
9

Calcium (Ca) is in the second column of the periodic table and is classified as an alkaline earth metal. Which of the following

formulas shows the ratio of a compound formed from Calcium and Bromine (Br)?A.
CaBr2

B.
CaBr

C.
CaBr3

D.
Ca2Br
Physics
1 answer:
enot [183]2 years ago
4 0

Answer:

CaI2

Explanation:

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If we start with 1.000 g of cobalt-60, 0.675 g will remain after 3.00 yr. this means that the of is _____
Tju [1.3M]
<span>Cobalt-60 is undergoing a radioactivity decay.

The formula of the decay is n=N(1/2)</span>∧(T/t).
<span>Where N </span>⇒ original mass of cobalt
<span>           n </span>⇒ remaining mass of cobalt after 3 years
          T ⇒ decaying period
           t ⇒ half-life of cobalt.

So,
0.675 = 1 × 0.5∧(3/t)
log 0.675 = log 0.5∧(3/t)
3/t = log 0.675 ÷log 0.5
 3/t= 0.567

t = 3÷0.567
  = 5.290626524

the half-life of Cobalt-60 is 5.29 years. 

<span>           
</span><span>
</span>
8 0
2 years ago
What work do you think is done when you carry a 20 N weight backpack for a 1000 m walk? will the work be positive, negative, or
dezoksy [38]

The work done is positive and is equal to 20000 J

<h3>What is work done?</h3>

Work done is defined as the product of force and the distance moved by the force.

Mathematically:

  • Work done = force * distance

The work done by the force = 20 * 1000 = 20000J

The work done is positive and is equal to 20000 J

Learn more about work done at: brainly.com/question/25923373

#SPJ1

8 0
1 year ago
an object has a length of 5.0 cm, aheight of 3.0 cm and a width of 15.0 cm. it has a mass of 24 grams. what is its density?
kondaur [170]
5x3=N
Nx15=F
Fx24=Your Awnser
5 0
2 years ago
Hey how has ur morning gone?
victus00 [196]

Answer:

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Explanation:

6 0
1 year ago
Calculate the torques about pivot P provided by the forces shown in the Figure 3, if L = 4.5 m
g100num [7]

The definition of torque of a force we can find the total torque on the bar is

           τ = 246.2 N m

The torque of a force is defined by the relation

         τ = F x r

where the bold letters indicate vectors, τ is the torque, f the force, and r the distance from the pivot point.

We can calculate the magnitude of this expression

       τ = F r sin θ

where in the angle between the forces and the candidate

In this case, we have five forces

  • the force at point P does not create torque since its distance is zero.
  • The force applied to the end of the bar, the angle is zero and the sine value zero.

The other forces create a torque:

F₁ =   80 N, the distance is x₁ = 0.5L,  θ₁ = 37º

F₂ = -60 N, the distance is x₂ = 0.5L, angle θ = 90º

F₃ =  70 N the distance is x₃ = L, angles θ = 30º

with respect to the vertical, this angle with respect to the horizontal is

         θ’ = θ + 90

         θ‘ = 30+ 90

         θ₃' = 120º

substitute

         τ = F₁ x₁ sin θ₁ + F₂ x₂ sin θ₂ + F₃ x₃ sin  θ₃'

let's calculate

          τ = 80 0.5L sin 37 - 60 0.5L sin 90 + 70 L sin 120

          τ = 54.7L

indicate that the length of the bar is L + 4.5 m

           τ = 54.7  4.5

           τ = 246.2 Nm

Using the defined torque we can find the total torque on the bar is

           τ = 246.2 N m

Learn more about torque here:

brainly.com/question/6855614

6 0
2 years ago
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