Answer:
its inertia.
Inertia is the tendency of an object to continue in the state of rest or of uniform motion
The electric potential difference is the electric potential energy per unit charge
Explanation:
First of all, we define the concept of electric potential. The electric potential is a measure of the gradient of the electric field at a certain point of the space. The electric potential at a distance
from a positive charge of magnitude
is given by

where k is the Coulomb's constant.
Now we can define the electric potential energy and the electric potential difference:
- Electric potential energy is the energy possessed by a charge due to the presence of an electric field. For a charge of magnitude
immersed in an electric field, its potential energy is given by
, where V is the electric potential at the location of the charge. - The electric potential difference is simply the difference in electric potential between two points in the space. For instance, if the potential at point A is V(A) and the potential at point B is V(B), then the potential difference is

The electric potential energy is also defined as the work done on a charge q moved through a potential difference of
. Consequently, the potential difference
represents the work per unit charge done, i.e. the work done when moving a unitary charge through a potential difference
.
Learn more about potential difference and current:
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#LearnwithBrainly
If someone is underground, then therefore there is less planet/ground underneath them, so there would be less gravity. Gravity directly affects weight.
Answer:
a) t =12[s]; b) x = 348[m]
Explanation:
We can solve this problem using the following kinematics equations:
a)

where:
vf = final velocity = 12 [m/s]
vo= initial velocity = 6 [m/s]
a = acceleration = 0.5[m/s^2]
t = time [s]
Now clearing the time t, we have:
![t=\frac{v_{f} -v_{o} }{a} \\t = \frac{12-6}{0.5} \\t=12[s]](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bv_%7Bf%7D%20-v_%7Bo%7D%20%7D%7Ba%7D%20%5C%5Ct%20%3D%20%5Cfrac%7B12-6%7D%7B0.5%7D%20%5C%5Ct%3D12%5Bs%5D)
b)
We can calculate the displacement for the first 12 [s] then using the equation for the constant velocity we can calculate the other displacement for the 20[s].
![v_{f}^{2}= v_{o}^{2}+2*a*x_{1} \\therefore\\x_{1} =\frac{v_{f}^{2}-v_{o}^{2}}{2*a} \\x_{1} =\frac{12^{2}-6^{2}}{2*.5}\\x_{1} =108[m]](https://tex.z-dn.net/?f=v_%7Bf%7D%5E%7B2%7D%3D%20%20v_%7Bo%7D%5E%7B2%7D%2B2%2Aa%2Ax_%7B1%7D%20%5C%5Ctherefore%5C%5Cx_%7B1%7D%20%3D%5Cfrac%7Bv_%7Bf%7D%5E%7B2%7D-v_%7Bo%7D%5E%7B2%7D%7D%7B2%2Aa%7D%20%5C%5Cx_%7B1%7D%20%3D%5Cfrac%7B12%5E%7B2%7D-6%5E%7B2%7D%7D%7B2%2A.5%7D%5C%5Cx_%7B1%7D%20%3D108%5Bm%5D)
The we can calculate the second displacement for the constant velocity:
![x_{2} =x_{o}+v*t_{2} \\ x_{2} =0+12*(20)\\x_{2} =240[m]](https://tex.z-dn.net/?f=x_%7B2%7D%20%3Dx_%7Bo%7D%2Bv%2At_%7B2%7D%20%5C%5C%20x_%7B2%7D%20%20%3D0%2B12%2A%2820%29%5C%5Cx_%7B2%7D%20%3D240%5Bm%5D)
x = x1 + x2
x = 108 + 240
x = 348[m]
Answer:
Emitted power will be equal to 
Explanation:
It is given factory whistle can be heard up to a distance of R=2.5 km = 2500 m
Threshold of human hearing 
We have to find the emitted power
Emitted power is equal to 


So emitted power will be equal to 