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goldenfox [79]
3 years ago
15

Why do we use the two-body problem to solve interplanetary trajectories, instead of including all of the appropriate gravitation

al forces that actually apply?
Physics
1 answer:
egoroff_w [7]3 years ago
6 0

Answer:

ur mom

hsheu7shrbrjxbfbbrndnifidfjf

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The transfer of energy by electromagnetic
chubhunter [2.5K]
Either convection or thermal energy
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3 years ago
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Two football players with mass 75kg and 100kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively, If the
Rina8888 [55]

Answer:

2 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = total momentum after collision

mu+m'u' = V(m+m') .................................Equation 1

Where m = mass of the first player, u = initial speed of the first player, m' = mass of the second player, u' = initial speed of the second player, V = combined speed of both players.

Making V the subject of the equation,

V = (mu+m'u')/(m+m')................ Equation 2

Note: Taking the direction of the first player as positive.

Given: m = 75 kg, m' = 100 kg, u = 6 m/s, u' = -8 m/s (opposite the first player),

Substituting into equation 2

V = [(75×6)+(100×(--8))]/(75+100)

V = (450-800)/175

V = 350/175

V = - 2 m/s.

Note: The negative signs tells that the combined speed is in the direction of the second player.

Hence the combined speed of the two players = 2 m/s

8 0
4 years ago
HELP ME DO THIS QUESTION PLEASE ​
raketka [301]

Answer:

i dont know

Explanation:

but what you can do is ask you mom or dad to get you a tutor to help you

7 0
3 years ago
A point charge is placed at the center of a spherical Gaussian surface. The electricflux ΦEischangedif(a) a second point charge
Simora [160]

Answer:

(b) the point charge is moved outside the sphere

Explanation:

Gauss' Law states that the electric flux of a closed surface is equal to the enclosed charge divided by permittivity of the medium.

\int\vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}

According to this law, any charge outside the surface has no effect at all. Therefore (a) is not correct.

If the point charge is moved off the center, the points on the surface close to the charge will have higher flux and the points further away from the charge will have lesser flux. But as a result, the total flux will not change, because the enclosed charge is the same.

Therefore, (c) and (d) is not correct, because the enclosed charge is unchanged.

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3 years ago
Displacement vectors of 4 km north, 2 km south, 5 km north, and 5 km south combine total displacement of
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B. 2 Km North, displacement is basically how far form the original place
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3 years ago
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