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vovikov84 [41]
3 years ago
11

A chocolate brownie has a volume of 360cubic centimeters and a mass of 270grams. Calculate its density.

Physics
1 answer:
il63 [147K]3 years ago
5 0

Answer:

  • Its density is 0.75 grams per cubic centimeters.

Explanation:

<u>Given that</u>:

  • A chocolate brownie has a volume of 360 cubic centimeters and a mass of 270 grams.

<u>To Calculate</u>:

  • Its density.

<u>We know that</u>:

  • Density = Mass/Volume

<u>We have</u>:

  • Mass = 270 g
  • Volume = 360 cc

<u>Finding its density</u>:

⟶ Density = 270/360

⟶ Density = 0.75

<u>Hence</u>,

  • Its density is 0.75 g/cc.
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Alex787 [66]

Explanation:

Given:

m = 1.673 × 10^-27 kg

Q = q = 1.602 × 10^-19 C

r = 0.75 nm

= 0.75 × 10^-9 m

A.

Energy, U = (kQq)/r

Ut = 1/2 mv^2 + 1/2 mv^2

1.673 × 10^-27 × v^2 = (8.99 × 10^9 × (1.602 × 10^-19)^2)/0.75 × 10^-9

v = 1.356 × 10^4 m/s

B.

F = (kQq)/r^2

F = m × a

1.673 × 10^-27 × a = ((8.99 × 10^9 × (1.602 × 10-19)^2)/(0.075 × 10^-9)^2

a = 2.45 × 10^17 m/s^2.

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3 years ago
A 783kg elevator rises straight up 164 meters. What is the potential energy of the elevator?
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Answer:

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8 0
2 years ago
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The pressure of air pushing down on a house roof is extremely large. Why is the roof not crushed?
Degger [83]
There is still air inside of a house, which is pushing the roof upwards, so the forces are equal and the roof is not crushed.
7 0
3 years ago
A uniformly charged sphere has a total charge of 300uc and a radius of 8cm. Find the electric field density at A point 16cm from
s2008m [1.1K]

E = <u>kQ</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

(r + h)²

where,

k = 9 × 10^9Nm²C^-2

Q = total charge, 300uC = 300 × 10^ -6C

r = 8 × 10^ -2m

h = 16 × 10^ -2m

then,

E = <u>9</u><u>e</u><u>9</u><u> </u><u>*</u><u> </u><u>3</u><u>0</u><u>0</u><u>e</u><u>^</u><u>-</u><u>6</u><u> </u><u> </u><u> </u><u> </u>

(8e^-2 + 16e^-2)²

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6 0
2 years ago
A jet plane flying 600 m/s experiences an acceleration of 4g when pulling out of the dive. What is the radius of curvature of th
Marina CMI [18]

Answer:

The radius of the curve is 9,183.67 m.

Explanation:

Given;

velocity of the jet plane, v = 600 m/s

acceleration of the jet plane, a = 4g = 4 x 9.8 m/s² = 39.2 m/s²

The radius of the curve is calculated from centripetal acceleration formula as given below;

a = \frac{v^2}{r} \\\\r = \frac{v^2}{a} \\\\r = \frac{600^2}{39.2} \\\\r = 9,183.67 \ m

Therefore, the radius of the curve is 9,183.67 m.

3 0
3 years ago
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