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Make I the subject E=VIt

slava [35]

To Make I the subject you need to get it by itself. To do this divide both sides by V and t:

I = E/Vt

5 0

2 years ago

What Are the type's of Tidal turbines?

Genrish500 [490]

Answer:

Types of tidal turbines

Axial turbines.

Crossflow turbines.

Flow augmented turbines.

Oscillating devices.

Venturi effect.

Tidal kite turbines.

Turbine power.

Resource assessment.

3 0

2 years ago

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Nicholas spends 20 minutes ironing shirts with his 1,800-watt iron. How many joules of energy were used

ivanzaharov [21]

Multiply the power (1,800 watts) by time (1,200 seconds) to get 2,160,000 joules (or 2.16 MJ)

7 0

2 years ago

Someone help please 1 You are cycling along a flat road. a Are you moving up or down? b What is the force that is pulling you

9966 [12]

Answer:

$\gamma \: 1a. \: i \: am \: moving \: downwards \: . \\ b. \: gravity \: is \: pulling \: me \: downwards \: \\ c. \: the \: force \: is \: acting \: downwards \: \\ the \: answer \: to \: the \: question \: c \: is \: downwars \: because \: its \: easy \: to \: pull \: the \: bike \: downwards \: but \: its \: hard \: to \: pull \: the \: bike \: upwards \: it \: would \: take \: more \: energy \: \gamma \\ \\$

Explanation:

<h3> $\infty \infty \: hope \: it \: helps \: you \: \\ have \: a \: good \: a \: day \: .$ </h3>

Slide my answer to see the full answer .

7 0

2 years ago

What is the electric potential of a 2.2 µC charge at a distance of 6.3 m from the charge? Recall that Coulomb’s constant is k =

iren2701 [21]

1) The electric potential at a distance r from a single point charge is given by
$V(r) = k \frac{q}{r}$
where k is the Coulomb's constant, q is the charge and r is the distance from the charge.

The charge in this problem is
$q=2.2 \mu C =2.2 \cdot 10^{-6} C$
So the potential at distance $r=6.3 m$ is
$V=k \frac{q}{r}=(8.99 \cdot 10^9 Nm^2 C^{-2}) \frac{2.2 \cdot 10^{-6} C}{6.3 m}=3139 V$

2) By using the same formula as before, we can find the electric potential at distance r=99 m from the charge:
$V=k \frac{q}{r}=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{2.2 \cdot 10^{-6} C}{99 m}=198 V$

3 0

3 years ago

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