Answer:
Explanation:
The equation for work is:
We can substitute the given values into the equation:
Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.
Ek = mv^2 / 2 — multiply both sides by 2
2Ek = mv^2 — divide both sides by m
2Ek / m = V^2 — switch sides
V^2 = 2Ek / m — plug in values
V^2 = 2*30J / 34kg
V^2 = 60J/34kg
V^2 = 1.76 m/s — sqrt of both sides
V = sqrt(1.76)
V = 1.32m/s (roughly)
Answer:
for the fill in the blanks
1- static
2-kinetic
3-coeffiecient
4-opposite to
5-sin theta
6-cos theta
im not sure however what to do with the top part or if its even part of what you need help with
Answer:
20 °C
Explanation:
Ideal gas law:
PV = nRT
Rearranging:
P / T = nR / V
Since n, R, and V are constant:
P₁ / T₁ = P₂ / T₂
488.2 kPa / T = 468 kPa / 281.15 K
T = 293.29 K
T = 20.1 °C
Rounded, the temperature was 20 °C.
Answer:
Lifting a bag of groceries
