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1 answer:
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Answer:
Explanation:
From the question we are told that:
Acceleration
Displacement
Initial time
Final Time
Generally the equation for Velocity of 1.05 travel is mathematically given by
Using Newton's Law of Motion
Generally the equation for Distance traveled before stop is mathematically given by
Generally the equation for Distance to stop is mathematically given by
Since For this Final section
Final velocity
Initial velocity
Therefore
Using Newton's Law of Motion
Giving
Therefore
Generally the Total Distance Traveled is mathematically given by
Answer:
a) -1.25 rev/s² and 23.3 rev
b) 2.67s
Explanation:
a) ω = (500 rev/min)(1min/ 60s) => 8.333 rev/s
ω= (200 rev/min)(1min/ 60s) => 3.333rev/s
time 't'= 4 s
angular acceleration 'α'=?
constant angular acceleration equation is given by,
ω= ω
+ α
t
α= (ω
- ω
)/t => (3.333-8.333)/4
α= -1.25 rev/s²
θ-θ = ω
t + 1/2α
t²
=(8.333)(4) + 1/2 (-1.25)(4)²
=23.3 rev
b) ω=0 (comes to rest)
ω = 3.333 rev/s
α= -1.25 rev/s²
ω= ω
+ α
t
t= (ω - ω
)/α
=> (0- 3.333)/-1.25
t= 2.67s