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Stolb23 [73]
3 years ago
13

What are the parameters that affect life and drag forces on an aerofoil?

Engineering
1 answer:
Vinil7 [7]3 years ago
6 0

Answer:

1.The velocity of fluid

2.Fluid properties.

3.Projected area of object(geometry of the object).

Explanation:

Drag force:

 Drag force is a frictional force which offered by fluid when a object is moving in it.Drag force try to oppose the motion of object when object is moving in a medium.

Drag force given as

F_D=\dfrac{1}{2}\rho\ A\ V^2

So we can say that drag force depends on following properties

1.The velocity of fluid

2.Fluid properties.

3.Projected area of object(geometry of the object).

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At high altitude air temperature is low and ice formation on wings can cause serious issues for air crafts.A solution to this pr
Hoochie [10]

Answer:

Check the explanation

Explanation:

The average heat Flux which sometimes can be called heat flux density, heat flow rate intensity or heat-flow density refers to the flow of energy per unit of area per unit of time. the units in SI are computed as watts per square metre (W.m^{-2}). It has both a magnitude as well as a direction and so it is a vector quantity.

The full step by step explanation to the question above can be seen in the attached image below.

5 0
3 years ago
Calculate the density of the FCC nickel lattice with an interstitial hydrogen in the centered position of the unit cell. You may
Anastaziya [24]

Answer:

\rho=8907.94\ Kg/m^3

Explanation:

Given that

a=3.524 A

At.Wt. ,M= 58.7 g/mole,

 For FCC

 Z = 4

4r=\sqrt2\ a

The density given as

\rho=\dfrac{ZM}{N_Aa^3}

\rho=\dfrac{4\times 58.7\times 10^{-3} }{ 6.023\times 10^{23}\times (3.524\times 10^{-10})^3}

\rho=8907.94\ Kg/m^3

So the density is \rho=8907.94\ Kg/m^3

4 0
3 years ago
A power screw is 30 mm in diameter and has a thread pitch of 5 mm. Find the thread depth, the thread width, the mean and root di
ankoles [38]

Answer:

thread depth = 2.5 mm

thread width = 2.5 mm

mean diameter = 27.5 mm

root diameter = 25 mm

lead of screw = 5 mm

Explanation:

given data

power screw diameter D = 30 mm

thread pitch  P = 5 mm

solution

First, we get here thread depth fr square thread

thread depth = \frac{P}{2}   ......................1

thread depth = \frac{5}{2}

thread depth = 2.5 mm

and

thread width for square thread

thread width = \frac{P}{2}   ......................2

thread width = \frac{5}{2}

thread width = 2.5 mm

and

mean diameter is

mean diameter = D - \frac{P}{2}    ................3

mean diameter = 30 - \frac{5}{2}

mean diameter = 27.5 mm

and

root diameter is

root diameter = D - P   ....................4

root diameter = 30 - 5

root diameter = 25 mm

and

lead of screw for single thread so n = 1

so lead of screw = 1 × 5

lead of screw = 5 mm

4 0
3 years ago
Need help<br> What is elasticity?
photoshop1234 [79]

Answer:

hope this helps,

Explanation:

brainliest please? :)

6 0
2 years ago
Read 2 more answers
Kkhghghglgghklghghghlk
RideAnS [48]

Answer:

hLDskjdbKSABCLABJC

Explanation:

BECAUSE

3 0
4 years ago
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