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3 years ago

What are the parameters that affect life and drag forces on an aerofoil?

Engineering

1 answer:

Vinil7 [7]3 years ago

6 0

Answer:

1.The velocity of fluid

2.Fluid properties.

3.Projected area of object(geometry of the object).

Explanation:

Drag force:

Drag force is a frictional force which offered by fluid when a object is moving in it.Drag force try to oppose the motion of object when object is moving in a medium.

Drag force given as

$F_D=\dfrac{1}{2}\rho\ A\ V^2$

So we can say that drag force depends on following properties

1.The velocity of fluid

2.Fluid properties.

3.Projected area of object(geometry of the object).

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What is the function and role of product tear down charts, and how do engineers utilize them in the reverse engineering process?

lora16 [44]

Answer:

Product Teardown 28 pieces (1) Plastic packaging: protect and display product for purchase. (4) Exterior screws: hold case halves together. (1) Right case half: acts as part of a handle and contains the rest of the parts. (1) Left case half: acts as part of a handle and contains the rest of the parts.

Explanation:

A product teardown process is an orderly way to know about a particular product and identify its parts, system functionality to recognize modeling improvement and identify cost reduction opportunities. Unlike the traditional costing method, tear down analysis collects information to determine product quality and price desired by the consumers.

7 0

3 years ago

Select the correct answer.

babunello [35]

Answer:

The information he needs next is;

B. Volume of paint needed per unit area

Explanation:

The operation Andy wants to perform = To apply paint on the walls of the house

The information Andy knows = The area of all walls in the house

The total volume of paint needed = The total area of the walls × The volume of paint needed for each unit area

Therefore, the information required is the volume of paint needed per unit area.

3 0

3 years ago

How's your day been so far? <3

Rzqust [24]

My day as been going awesome

7 0

3 years ago

Two very long concentric cylinders of diameters D1 = 0.42 m and D2 = 0.5 m are maintained at uniform temperatures of T1 = 950 K

MrRa [10]

Answer:

Q=33.34 KW/m

Explanation:

Given that

D₁=0.42 m

A₁= π D₁ L

For unit length

A₁= π D₁ = 0.42 π m²

D₂=0.5 m

A₂= 0.5 π m²

ε₁= 1 ,ε₂= 0.55

T₁=950 K ,T₂ = 500 K

$Q=\dfrac{\sigma (T_1^4-T_2^4)}{\dfrac{1-\varepsilon _1}{A_1\epsilon _1}+\dfrac{1-\varepsilon _2}{A_2\epsilon _2}+\dfrac{1}{A_1F_{12}}}$

F₁₁+F₁₂= 1

F₁₁= 0

So, F₁₂= 1

$Q=A_1\dfrac{\sigma (T_1^4-T_2^4)}{\dfrac{1-\varepsilon _1}{\epsilon _1}+A_1\dfrac{1-\varepsilon _2}{A_2\epsilon _2}+1}$

$Q=0.42\pi \dfrac{5.67\times 10^{-8}(950^4-500^4)}{\dfrac{1-1}{1}+0.42\pi\times \dfrac{1-0.55}{0.5\pi\times 0.55}+1}$

Q=33.34 KW/m

3 0

4 years ago

Consider the following chain-reaction mechanism for the high-temperatureformation of nitric oxide, i.e., the Zeldovich mechanism

vagabundo [1.1K]

Answer: hello attached below is the properly written chain reaction to your question

answer :

d[NO] / dt = $k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] + K_{3f}[N][OH]$

d[N] / dt = $k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] - K_{3f}[N][OH]$

Explanation:

<u>write out expressions for d[NO] / dt and d[N] / dt</u>

Given :

properly written chain reaction ( attached below)

Expression for d[NO] / dt can be written as

$k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] + K_{3f}[N][OH]$

Expression for d[N] / dt can be written as

$k_{1f} [O] [N_{2}] + K_{2f} [N][O_{2} ] - K_{3f}[N][OH]$

8 0

3 years ago