When a slender member is subjected to an axial compressive load, it may fail by a ... Consider a column of length, L, cross-sectional Moment of Inertia, I, having Young's Modulus, E. Both ends are pinned, meaning they can freely rotate ... p2EI L2 ... scr, is the Euler Buckling Load divided by the columns cross-sectional area
Answer:
Impossible.
Explanation:
The ideal Coefficient of Performance is:


The real Coefficient of Performance is:


Which leads to an absurds, since the real Coefficient of Performance must be equal to or lesser than ideal Coefficient of Performance. Then, the cycle is impossible, since it violates the Second Law of Thermodynamics.
29.4 bro I hope that helps
Answer:
Part A:

CPI cannot be negative so it is not possible to for program to run two times faster.
Part B:

CPI reduced by
=80%
Part C:
New Execution Time=
Increase in speed=
Explanation:
FP Instructions=50*106=5300
INT Instructions=110*106=11660
L/S Instructions=80*106=8480
Branch Instructions=16*106=1696
Calculating Execution Time:
Execution Time=
Execution Time=
Execution Time=
Part A:
For Program to run two times faster,Execution Time (Calculated above) is reduced to half.
New Execution Time=

CPI cannot be negative so it is not possible to for program to run two times faster.
Part B:
For Program to run two times faster,Execution Time (Calculated above) is reduced to half.
New Execution Time=

CPI reduced by
=80%
Part C:

New Execution Time=
New Execution Time=
Increase in speed=