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4 years ago

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(40%) A bank wants to store the account number of its customers (an 8-digit number) in encrypted form on magnetic stripe ATM car

ds. Discuss the security of the following methods for storing the account number against an attacker who can read the magnetic stripe: (1) store a cryptographic hash of the account number; (2) store the ciphertext of the account number encrypted with the bank's public key using a public-key cryptosystem; (3) store the ciphertext of the account number encrypted with the bank's secret key using a symmetric cryptosystem.

1 answer:

9966 [12]4 years ago

3 0

Answer:

Explanation:

Attached is the solution to the question

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Baleykdoyle ANSWRER THISSSS NOWWWW FAST

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Answer:Ballydoyle is a racehorse training facility located in County Tipperary in Ireland. It is a sister thoroughbred facility to Coolmore Stud, and both are owned by John Magnier, son in law to the racehorse trainer Vincent O'Brien.

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Why did you choose agricultural and biosystem as a course? Help me guys

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Answer:

To be able to develop as a human and give back to the community. To ensure that people have safe food and water to drink, clean fuel and energy sources, and in general a safe enviornment to live in.

Explanation:

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3 years ago

A rigid canister with a radius of 5 in and a height of 10 in is filled with air. The initial pressure and temperature of air in

Elza [17]

Answer:1.458 Btu

Explanation:

Given

radius of canister $\left ( r\right )=5in$

Height of canister $\left ( h\right )=10 in.$

Initial pressure $\left ( P_i\right )=14.7 Psi$

Initia ltemprature $\left ( T_i\right )=70^{\circ}F$

Final pressure $\left ( P_f\right )=30Psi$

as canister is rigid therefore change in volume is zero

therefore

$\frac{P_i}{T_i}$ = $\frac{P_f}{T_f}$

$\frac{14.7}{70}$ = $\frac{30}{T_f}$

$T_f=142.85^{\circ}F$

volume of canister= $\pi \times r^{2}\times h$

= $\pi \times 5^{2}\times 10=250\pi$

volume of canister=12872,038.8 $mm^3$

now calculating mass of air

PV=mRT

substituting values

$\left ( 14.7Psi\right )\left ( 12872,038.8 mm^3\right )=m\left ( 0.287\right )\left ( 70^{\circ}F\right )$

m=21.0192 gm

Therefore heat transferred = $mc_p\left ( T_f-T_i\right )$

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4 years ago

Which of the following Python lines calculates the standard deviation of variables Exam1 and Exam4 from a CSV file called ExamSc

Virty [35]

Answer:

The option B calculates the standard deviation of variables Exam1 and Exam4.

Explanation:

First, let's write the first two lines correctly:

import pandas as pd
scores = pd.read_csv('ExamScores.csv')

Now, let's analyse each option:

- The option A is incorrect

The expression std[['Exam1','Exam4']] is the incorrect part because in this case std is working as a variable and the std was not previously declared. So it will generate an error.

- The option C is incorrect

The expression std[['Exam1','Exam4']].scores() is incorrect because of two reasons: first, std is working as a variable and the std was not previously declared (as in option A), second, .scores() is working as a method and in this case, scores is the variable. So it will generate an error.

- The option D is incorrect

The expression [['Exam1']] is the incorrect part because it doesn't include the 'Exam4' and the problem is asking for the standard deviation of variables Exam1 and Exam4.

- The option B is CORRECT

The expression std[['Exam1','Exam4']] refers to the variables Exam1 and Exam4 from the total exams. As scores is a pandas variable and .std() is a method provided by pandas library, the expression .std() allows to get the deviation standard of the variables Exam1 and Exam4.

Thus, the option B calculates the standard deviation of variables Exam1 and Exam4.

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3 years ago

Water from an upper tank is drained into a lower tank through a 5 cm diameter iron pipe with roughness 2 mm. The entrance to the

nignag [31]

Answer:

Relative roughness = 0.04

Explanation:

Given that:

Diameter = 5 cm

roughness = 2 mm

At inlet:

Minor coefficient loss $k_{L1} = 0.4$

At exit:

Minor coefficient loss $k_{L2} = 1$

Height h = 4m

Length = 5 m

To find the relative roughness:

Relative roughness is a term that is used to describe the set of irregularities that exist inside commercial pipes that transport fluids. The relative roughness can be evaluated by knowing the diameter of the pipe made with the absolute roughness in question. If we denote the absolute roughness as e and the diameter as D, the relative roughness is expressed as:

$e_r = \dfrac{e}{D}$

$e_r = \dfrac{0.2 }{5}$

$\mathbf{e_r = 0.04}$

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3 years ago