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kolbaska11 [484]
3 years ago
15

A piston-cylinder assembly contains 3 kg of water, initially at 0.06 bar and 160 C. The water undergoes two processes in series:

D a constant volume process to saturated vapor followed by a cooling process. At the end of the cooling process, the temperature is 20 C and the water is a liquid-vapor mixture with a quality of 25%. Neglect kinetic and potential energy effects. i. (12) Determine the specific volume and specific internal energy of the water at a the initial state, b. the state at the end of the constant volume process, and li. (4) Sketch the T-v and p-v diagrams showing the key states, the ili (6) Find the work and heat transfer for the constant volume process, both in iv. (3) If 5500 KJ of heat is removed from the system during the cooling, c. the state at the end of the cooling process. processes, and relevant isobars or isotherms, kJ, calculate the work and comment whether this work is done on the system or by the system.

Engineering
1 answer:
schepotkina [342]3 years ago
3 0

Answer:

See attachment below

Explanation:

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Advantages of data analysis

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3 years ago
A simply supported wood roof beam is loaded with single point dead and roof live loads applied at midspan (PD = 400 lb, PLr = 16
Lynna [10]

Answer:mold i belive

Explanation:

3 0
3 years ago
Compact fluorescent bulbs are much more efficient at producing light than are ordinary incandescent bulbs. They initially cost m
Ilia_Sergeevich [38]

Answer:

ordinary bulb total cost is $39.54

fluorescent bulb total cost is $13.05

amount save = 39.54 - 13.05 = $26.49

resistance = 626.1 ohm

Explanation:

in the 1st part

bulb on time = 3 year = 4380 hours

life of bulb = 750 h

so number of bulb required = \frac{4380}{750}

number of bulb required = 6

cost of 6 bulb is = 6 × 0.75 = $4.5

so

cost of operation is = 100 × 4380 × \frac{0.08}{1000}

cost of operation = $35.04

so total cost will be = $4.5 + $35.04  = $39.54

and

when compare with florescent bulb

time = 3 year = 4380 h

life of bulb = 10000 h

so number of bulb required = \frac{4380}{10000}

number of bulb required = 0.43 = 1

cost of 6 bulb is = 1 × 5 = $5

so

cost of operation is = 23 × 4380 × \frac{0.08}{1000}

cost of operation = $8.05

so total cost will be = $5 + $8.05  = $13.05

in part 2nd

total amount save while compare bulb is

amount save = 39.54 - 13.05 = $26.49

and in part 3rd

resistance of bulb is

resistance = \frac{v^2}{P}

resistance = \frac{120^2}{23}

resistance = 626.1 ohm

6 0
3 years ago
To assist in completing this question, you may reference the Animated Technique Video - MALDI-TOF Mass Spectroscopy. Complete th
a_sh-v [17]

Complete Question

The complete question is shown on the first uploaded image.

Answer:

The answer is shown on the second uploaded image

Explanation:

The explanation is also shown on the second uploaded image

3 0
3 years ago
A labor-intensive process to manufacture a product has a fixed cost of $338,000 and a variable cost of $143 per unit. An automat
ozzi

Answer:

no of unit is 17941

Explanation:

given data

fixed cost = $338,000

variable cost = $143 per unit

fixed cost = $1,244,000  

variable cost = $92.50 per unit

solution

we consider here no of unit is = n

so here total cost of labor will be sum of fix and variable cost i.e

total cost of labor = $33800 + $143 n  ..........1

and

total cost of capital intensive  = $1,244,000 + $92.5 n   ..........2

so here in both we prefer cost of capital if cost of capital intensive less than cost of labor

$1,244,000 + $92.5 n  <  $33800 + $143 n

solve we get

n > \frac{906000}{50.5}

n > 17941

and

cost of producing less than selling cost so here

$1,244,000 + $92.5 n < 197 n

solve it we get

n > \frac{1244000}{104.5}  

n > 11904

so in both we get greatest no is 17941

so no of unit is 17941

3 0
3 years ago
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