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kolbaska11 [484]
3 years ago
15

A piston-cylinder assembly contains 3 kg of water, initially at 0.06 bar and 160 C. The water undergoes two processes in series:

D a constant volume process to saturated vapor followed by a cooling process. At the end of the cooling process, the temperature is 20 C and the water is a liquid-vapor mixture with a quality of 25%. Neglect kinetic and potential energy effects. i. (12) Determine the specific volume and specific internal energy of the water at a the initial state, b. the state at the end of the constant volume process, and li. (4) Sketch the T-v and p-v diagrams showing the key states, the ili (6) Find the work and heat transfer for the constant volume process, both in iv. (3) If 5500 KJ of heat is removed from the system during the cooling, c. the state at the end of the cooling process. processes, and relevant isobars or isotherms, kJ, calculate the work and comment whether this work is done on the system or by the system.

Engineering
1 answer:
schepotkina [342]3 years ago
3 0

Answer:

See attachment below

Explanation:

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A rigid insulated tank is divided into 2 equal compartments by a thin rigid partition. One of the compartments contains air, ass
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6 0
3 years ago
Water flows through a pipe and enters a section where the cross sectional area is larger. Viscosity, friction, and gravitational
BaLLatris [955]

Answer:

(A) and (D)

Explanation:

1) P2 is less than P1, that is when P1 increases in pressure, the velocity V1 of the water also increases. Therefore, on the other hand, since P2 is directly proportional to V1, P2 and V2 will be less than P1 and V1 respectively.

2) For P2 greater than P1 and V2 also is greater than V1. Since P2 is directly proportional to V2, hence, when P2 increases in pressure, P1 reduces in pressure. Similarly, velocity, V2 also increases and V1 reduces.

3 0
3 years ago
What is the De Broglie wavelength of an electron under 150 V acceleration?
yanalaym [24]

Answer:

0.1 nm

Explanation

Potential deference of the electron is given as V =150 V

Mass of electron m=9.1\times 10^{-31}

Let the velocity of electron = v

Charge on the electron =1.6\times 10^{-19}C

plank's constant h =6.67\times 10^{-34}

According to energy conservation eV =\frac{1}{2}mv^2

v=\sqrt{\frac{2eV}{M}}=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 150}{9.1\times 10^{-31}}}=7.2627\times 10^{-6}m/sec

Now we know that De Broglie wavelength \lambda =\frac{h}{mv}=\frac{6.67\times 10^{-34}}{9.1\times 10^{-31}\times 7.2627\times10^6 }=0.100\times 10^{-9}m=0.1nm

4 0
3 years ago
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HELP! Need the correct answer ASAP! Thanks
Bess [88]

Answer:

i think it might be answer b

Explanation:

7 0
3 years ago
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