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IrinaK [193]
3 years ago
5

2.18 The net potential energy between two adjacent ions, EN, may be represented by the following equation: (1) Calculate the bon

ding energy E0 in terms of the parameters A, B, and n using the following procedure: 1. Differentiate EN with respect to r, and then set the resulting expression equal to zero, since the curve of EN versus r is a minimum at E0. 2. Solve for r in terms of A, B, and n, which yields r0, the equilibrium interionic spacing. 3. Determine the expression for E0 by substitution of r0 into Equation (1).
Engineering
1 answer:
goblinko [34]3 years ago
3 0

Answer:

2.18

Explanation:

because ya correc

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In manufacturing a particular set of motor shafts, only shaft diameters of between 38.00 and 37.50 mm are usable. If the process
Masteriza [31]

Answer:

P(37.5

And we can find this probability with this difference:

P(-2.5

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-2.5

So then the percentage usable are 94,6%

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the diameters of a population, and for this case we know the distribution for X is given by:

X \sim N(37.8,0.12)  

Where \mu=37.8 and \sigma=0.12

We are interested on this probability

P(37.5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(37.5

And we can find this probability with this difference:

P(-2.5

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-2.5

So then the percentage usable are 94,6%

4 0
3 years ago
g Calculate a better value for the convection coefficient using resources from heat transfer. Assume forced convection of the ai
ollegr [7]

Answer:results for h should on the same order of magnitude of the value I provided. If it isn't, check your units. Update to you calculated values for h and resolve your model.

Explanation:

4 0
3 years ago
The Acme threading tool forms an inc luded angle of how many degrees? A. 30 B. 55 C. 29 D. 60
Schach [20]

Answer:

(C) 29°

Explanation:

ACME THREAD ANGLE : it is the angle measured between the thread axis and thread the thread flanks, with the help of thread angle we calculate the shape of screw thread it is the mean of v thread and square thread  the acme thread angle is denoted by β every thread has its own charactersistics which depends on the pitch and diameter of the thread

4 0
4 years ago
A group of statisticians at a local college has asked you to create a set of functions that compute the median and mode of a set
iVinArrow [24]

Answer:

Functions to create a median and mode of a set of numbers

Explanation:

def median(list):

   if len(list) == 0:

       return 0

   list.sort()

   midIndex = len(list) / 2

   if len(list) % 2 == 1:

       return list[midIndex]

   else:

       return (list[midIndex] + list[midIndex - 1]) / 2

def mean(list):

   if len(list) == 0:

       return 0

   list.sort()

   total = 0

   for number in list:

       total += number

   return total / len(list)

def mode(list):

   numberDictionary = {}

   for digit in list:

       number = numberDictionary.get(digit, None)

       if number == None:

           numberDictionary[digit] = 1

       else:

           numberDictionary[digit] = number + 1

   maxValue = max(numberDictionary.values())

   modeList = []

   for key in numberDictionary:

       if numberDictionary[key] == maxValue:

           modeList.append(key)

   return modeList

def main():

   print "Mean of [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]: ", mean(range(1, 11))

   print "Mode of [1, 1, 1, 1, 4, 4]:", mode([1, 1, 1, 1, 4, 4])

   print "Median of [1, 2, 3, 4]:", median([1, 2, 3, 4])

main()

3 0
4 years ago
Read 2 more answers
Use a passband of 0 to 5 kHz with 5 kHz cutoff frequency and filter to attenuate all frequencies at and above 10 kHz by at least
Alinara [238K]

Answer:

See attached picture for answer.

Explanation:

See attached picture for explanation.

5 0
3 years ago
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