A teacher wishes to determine the reliability of three trials on a performance test. she uses anova to obtain the reliability co
1 answer:
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Answer:
1. Total interest rate is $166,790
2. Refer to the attached file for the straight-line amortization table for the bonds' life.
3.
To record interest rate paid in 30th June 2018:
Dr Interest expenses 16,679
Dr Premium on bond payable 4,521
Cr Cash 21,200
To record interest rate paid in 31st Dec 2018:
Dr Interest expenses 16,679
Dr Premium on bond payable 4,521
Cr Cash 21,200
Explanation:
Total interest rate as followed : Interest payment - Premium on bond payable = 530,000 x 8% /2 x 10 - (575,210 - 530,000) =166,790.
Answer:
The answer is 27,408.71
Explanation:
Solution
Recall that:
You were left with a trust fund of =$100,00
Interest rate = 6.5%
Money with drawled = 4 installments
Now,
The step to take is to find you could withdraw currently at the start of each of the next 3 years with a zero account to end up with.
Now,
100, 00 = X (1 - (1.065)^-4/.065/1.065
We now solve for X
Thus
X =7,408.71
By applying or using a financial calculator
We arrange it to an annuity due setting - [2nd] [BGN] then [2nd] [Set] this will set it to mode "BGN"
So,
N = 4
I/Y = 6.5
PV = -100,000
FV = 0
CPT PMT
The payments are known to to be 27,408.71
Note : Kindly find an attached copy of the Financial calculator below
