All categories

3 years ago

What is the value of X in the given triangle?

Mathematics

1 answer:

miskamm [114]3 years ago

4 0

<h3>Answer: x = 65.4</h3>

==================================================

Work Shown:

cos(angle) = adjacent/hypotenuse

cos(x) = 5/12

x = arccos(5/12)

x = 65.375681647836 which is approximate

x = 65.4 after rounding to one decimal place

Make sure your calculator is in degree mode. The arccosine function is the same as the inverse cosine function (shortened to $\cos^{-1}$ ).

You might be interested in

Need help ASAP !!!!!

Flura [38]

Answer:

Step-by-step explanation:

12x + 20+40 = 180

12x = 120

X = 10

6 0

3 years ago

Angle 5 measures 90 degrees and angle 1 measures 40 degrees fill in the other angle measures just put it the number.

Serggg [28]

Answer:

sorry for being late

1=40

2=50

3=50

4=130

5=90

Step-by-step explanation:

3 0

3 years ago

I need help finding the equation of the line. Could someone please help me? Thanks.

anyanavicka [17]

The slope is 2/3, and the y-intercept is 4. In slope intercept form, the equation is y=2/3x+4

3 0

3 years ago

A number k is less than 3 units from 10. <br> What's the absolute value inequality???

Brrunno [24]

It would be: k+3 = 10

subtracting 3 from both sides,

k+3-3 = 10-3

k=7

6 0

3 years ago

Solve y=f(x) for x. Then find the input when the output is -3.

DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(x-5\right)^3-1$

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

$\:\:y=\:\left(x-5\right)^3-1$

$-3\:=\:\left(x-5\right)^3-1\:\:\:$

switch sides

$\left(x-5\right)^3-1=-3$

Add 1 to both sides

$\left(x-5\right)^3-1+1=-3+1$

$\left(x-5\right)^3=-2$

$\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

Thus, the input values are:

$x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}$

And the real input is:

$x=-\sqrt[3]{2}+5$

$x=3.74$

4 0

3 years ago