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Andreyy89
3 years ago
10

Find the volume of a hemisphere that has a diameter of 48 inches and leave your answer in terms of pie

Mathematics
1 answer:
marin [14]3 years ago
8 0

<u>Given</u>:

Given that the diameter of the hemisphere is 48 inches.

We need to determine the volume of the hemisphere.

<u>Radius:</u>

The radius of the hemisphere can be determined using the formula,

r=\frac{d}{2}

Substituting d = 48, we get;

r=\frac{48}{2}

r=24

Thus, the radius of the hemisphere is 24 inches.

<u>Volume of the hemisphere:</u>

The volume of the hemisphere can be determined using the formula,

V=\frac{2}{3} \pi r^3

Substituting r = 24, we get;

V=\frac{2}{3} \pi (24)^3

V=\frac{2}{3} \pi (13824)

V=9216 \pi \ in^3

Thus, the volume of the hemisphere is 9216π cubic inches.

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If you draw a card with a value of three or less from a standard deck of cards, I will pay you $43, If not, you pay me $11 (Aces
mrs_skeptik [129]

Answer:

$1.46

Step-by-step explanation:

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There are 4 cards of each in a total of 52 cards ;

Therefore, number of winning cards ;

(4 * 3) = 12 cards

Hence,

P(winning) = 12 / 52 = 3 / 13

P(not winning) = 1 - 3 /13 = (13 - 3) / 13 = 10/13

Earning (X)

Amount earned for winning = $43

Amount lost for not winning = $11

X ___ $43 ______ - $11

P(X) _ 3/13 _______ 10/13

Expected value, E(X) = ΣX*P(X)

Σ(X) = (43 * 3/13) + (-11 * 10/13)

E(X) = 9.9230769 - 8.4615384

E(X) = 1.4615385

E(X) = $1.46

8 0
2 years ago
Which function has real zeros at x = 3 and x = 7?
Fynjy0 [20]
If it has real zeros at x=3 and 7, the factors of f(x) are:

(x-3)(x-7) so f(x) is

f(x)=x^2-10x+21
3 0
3 years ago
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Lubov Fominskaja [6]

Answer:

The answer is " \sqrt[8]{2^5} ".

Step-by-step explanation:

Given value:

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They have a shared denominator. It's least that is equally divided

among 8 or 2 is 8:

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\to \frac{7-2}{8}\\\\\to \frac{5}{8}\\\\

This gives us:

\to 2 \frac{5}{8}

As rational notation is written as extremists, that root was its denominator as well as the power seems to be the numerator.

Which means 8 is the root and 5 the force that gives us:

\sqrt[8]{2^5}

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