Question

Which graph shows a set of ordered pairs that represent a function?

Answer 1

A function must associate only one output to each input. So, you must rule out all the ordered pairs that associate two outputs to the same input.

In the first answer we have both $(2,-1)$ and $(2,-3)$. So, this is not a function because there is ambiguity defining $f(2)$. Should it be $f(2)=-1$ or $f(2)=-3$?

In the second answer we have both $(4,-3)$ and $(4,-4)$. So, this is not a function because there is ambiguity defining $f(4)$. Should it be $f(4)=-3$ or $f(4)=-4$?

The third answer is a function because all input-output associations are unique: we have

$f(-3)=2,\ \ f(-2)=2,\ \ f(0)=1,\ \ f(1)=3,\ \ f(2)=-4,\ \ f(4)=-1$

In the fourth answer we have both $(-2,1)$ and $(-2,-1)$. So, this is not a function because there is ambiguity defining $f(-2)$. Should it be $f(-2)=1$ or $f(-2)=-1$?

Answer 2

Answer:

c is a function

Step-by-step explanation: