Question: A car with a mass of 800 g and velocity of 15 m/s collided with a truck moving in opposite direction with a velocity of 20 m/s, if the momentum is conserved and they both move with a common velocity of 10 m/s, what is the mass of the truck?
Answer:
0.133 kg
Explanation:
Applying the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
mu+m'u' = V(m+m')................... Equation 1
Where m = mass of the car, m' = mass of the truck, u = initial velocity of the car, u' = initial velocity of the truck, V = common velocity.
From the question,
Given: m = 800 g = 0.8 kg, u = 15 m/s, u' = -20 m/s, V = 10 m/s
Substitute these values into equation 2
(0.8*15)+(m'*20) = 10(0.8+m')
Solve for m'
12-20m' = 8+10m'
-20m'-10m' = 8-12
-30m' = -4
m' = -4/-30
m' = 0.133 kg
To solve this problem we will apply the concepts of acceleration according to the laws of kinetics. Acceleration can be defined as the change in velocity per unit time, that is,

Here,
v = Final velocity
u = Initial velocity
t = Time
Rearranging to find the initial velocity,

Now the acceleration is equal to the gravity, then,



The velocity of the shell at 5.5s after the launch is,




Therefore the magnitude of the velocity of the shell at 5.5s is -19.26m/s
It is often revealed <span>at the resolution of the story, when the reader can see how the story ends.</span>
Answer:
The right solution is "126 Psi".
Explanation:
The given values are:
P₁ = 130 psig
i.e.,
= 
= 
or,
= 
Z₂ = 10ft
= 3.05 m
= 1000 kg/m³
According to the question,
Z₁ = 0
V₁ = V₂
As we know,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
i.e.,
⇒ 
⇒ 