3 years ago

Any science peeps pls help

1 answer:

8 0

Just list facts about cardiovascular and lymphatic system separately and then search stuff about how they work together.

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Three charges are on a line. A positive charge is on the far left labeled q Subscript 1 baseline positive 6 Coulombs. The second

tiny-mole [99]

Answer:

–1.1 × 10^11 N

Explanation:

I did the assignment

4 0

3 years ago

Which of the following statements is true?

likoan [24]

Answer:

d.Energy as heat transferred into an object is determined by the amount of work done on the object.

Explanation:

4 0

3 years ago

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During a workout, the football players at State U ran up the stadium stairs in 61 s. The stairs are 130 m long and inclined at a

NeTakaya

Answer:

P = 1097 Watt

Explanation:

given,

length of stairs, L = 130 m

inclination with horizontal,θ = 30°

mass of the football player = 105 Kg

time = 61 s

we know,

$Power = \dfrac{work}{time}$

Work = change in Potential energy

h = L sin 30°

h = 130 x 0.5

h = 65 m

W = m g h

W = 105 x 9.8 x 65

W = 66885 J

now,

$P = \dfrac{66885}{61}$

P = 1097 Watt

hence, the power output on the way is 1097 W

5 0

3 years ago

Hazardous wastes are placed into categories to aid in _____.

torisob [31]

The waste that poses substantial or potential threats to public and environment health
Hazardous waste are actually defined as RCRA in 40 CFR 261 the the four hazardous traits are
ignitability
reactivity
corrosivity
toxicity
i think its b

4 0

3 years ago

Read 2 more answers

A tennis ball is thrown from a 25 m tall building with a zero initial velocity. At the same moment, another ball is thrown from

Nataly [62]

Answer:

The two balls meet in 1.47 sec.

Explanation:

Given that,

Height = 25 m

Initial velocity of ball= 0

Initial velocity of another ball = 17 m/s

We need to calculate the ball

Using equation of motion

$s=ut+\dfrac{1}{2}gt^2+h$

Where, u = initial velocity

h = height

g = acceleration due to gravity

Put the value in the equation

For first ball

$s_{1}=0-\dfrac{1}{2}gt^2+25$ ....(I)

For second ball

$s_{2}=17t-\dfrac{1}{2}gt^2+0$ ....(II)

From equation (I) and (II)

$-\dfrac{1}{2}gt^2+25=17t-\dfrac{1}{2}gt^2+0$

$t=\dfrac{25}{17}$

$t=1.47\ sec$

Hence, The two balls meet in 1.47 sec.

6 0

3 years ago