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Fantom [35]
3 years ago
6

A block of mass m is initially moving to the right on a horizontal frictionless surface at a

Physics
2 answers:
slava [35]3 years ago
7 0

Answer:

The distance that the spring compresses is:

v\sqrt{\frac{m}{k}}

Explanation:

<u>Kinetic and Elastic Potential Energy</u>

The kinetic energy of an object of mass m traveling at a speed v is:

\displaystyle K=\frac{1}{2}mv^2

The elastic potential energy of a spring of constant k that compresses a distance x is:

\displaystyle E=\frac{1}{2}kx^2

The block of mass m is moving at a speed v when compresses a spring of constant k. The kinetic energy will eventually transform into elastic energy, but before that, both energies will be equal. It happens when:

\displaystyle \frac{1}{2}mv^2=\frac{1}{2}kx^2

Simplifying:

\displaystyle mv^2=kx^2

Dividing by k:

\displaystyle x^2=\frac{mv^2}{k}

Taking square root:

\displaystyle x=\sqrt{\frac{mv^2}{k}}=v\sqrt{\frac{m}{k}}

The distance that the spring compresses is \mathbf{v\sqrt{\frac{m}{k}}}

Troyanec [42]3 years ago
7 0

Answer:

Explanation:

KE=PE

1/2mv^2=1/2kx^2

2(1/2mv^2)=2(1/2kx^2)

MV^2=kX^2

(MV^2)/k=X^2

X=√(mv^2)/k

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A video game includes an asteroid that is programmed to move in a straight line across a 17-inch monitor according to the equati
Ainat [17]

Answer:

The asteroid's acceleration at this point is 2.71\ m/s^2

Explanation:

The equation that governs the trajectory of asteroid is given by :

x=6.5t-2.3t^3

The velocity of asteroid is given by :

v=\dfrac{dx}{dt}\\\\v=\dfrac{d(6.5t-2.3t^3)}{dt}\\\\v=6.5-6.9t^2

At some point during the trip across the screen, the asteroid is at rest. It means, v = 0

So,

6.5-6.9t^2=0\\\\t=0.971\ s                      

Acceleration,

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6.5-6.9t^2)}{dt}\\\\a=-13.8t                        

Put t = 0.971 s

a=-13.8\times 0.197\\\\a=-2.71\ m/s^2

So, the asteroid's acceleration at this point is 2.71\ m/s^2 and it is decelerating.

6 0
3 years ago
4) Write down the transformation of energy in torch light.<br>​
Elenna [48]

Answer:

<u>The transformation of energy in a torch light is as follows:</u>

1) When the torch is turned ON, the chemical energy in the batteries is converted into electrical energy.

2) The electrical energy is converted into heat and light energy. (We feel the torch to be hot after some time and we can see the light energy)

Hope this helped!

<h2>~AnonymousHelper1807</h2>
7 0
3 years ago
Whats the net force​
zavuch27 [327]

Answer:

13n pushing left

Explanation:

1563 - 1550

3 0
3 years ago
A crate rests on a flatbed truck which is initially traveling at 17.9 m/s on a level road. The driver applies the brakes and the
Mamont248 [21]

Answer:

The minimum coefficient of friction required is 0.35.  

Explanation:

The minimum coefficient of friction required to keep the crate from sliding can be found as follows:

-F_{f} + F = 0      

-F_{f} + ma = 0      

\mu mg = ma

\mu = \frac{a}{g}

Where:

μ: is the coefficient of friction

m: is the mass of the crate

g: is the gravity

a: is the acceleration of the truck

The acceleration of the truck can be found by using the following equation:

v_{f}^{2} = v_{0}^{2} + 2ad

a = \frac{v_{f}^{2} - v_{0}^{2}}{2d}

Where:  

d: is the distance traveled = 46.1 m

v_{f}: is the final speed of the truck = 0 (it stops)      

v_{0}: is the initial speed of the truck = 17.9 m/s

a = \frac{-(17.9 m/s)^{2}}{2*46.1 m} = -3.48 m/s^{2}        

If we take the reference system on the crate, the force will be positive since the crate will feel the movement in the positive direction.  

\mu = \frac{a}{g}  

\mu = \frac{3.48 m/s^{2}}{9.81 m/s^{2}}

\mu = 0.35

Therefore, the minimum coefficient of friction required is 0.35.  

I hope it helps you!

4 0
3 years ago
Convertir 1200 ms a cs<br> Convertir 0,3 mm a cm.
Vaselesa [24]

Answer:

You can do the reverse unit conversion from cm/s to m/s, or enter any two units below: Metre per second (U.S. spelling: meter per second) is an SI derived unit of both speed (scalar) and velocity (vector quantity which specifies both magnitude and a specific direction), defined by distance in metres divided by time in seconds.

Explanation:

3 0
3 years ago
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