1. Which of the following statements is NOT true about double-replacement reactions?

2 answers:

7 0

1 is D - double-replacements do not make solid metals
2 is A - to have complete combustion the original compound must ONLY have C, H and O
3 is B - the elemental Mg replaces the H in the HCl

kolbaska11 [484]3 years ago

4 0

The first one is going to likely be A because this is what happens in a precipitation reaction, not in a double replacement reaction. The second one is A because that is Methane, which is a source of fuel. The complete combustion formula is Oxygen + fuel, resulting in CO2 and H2O. The final one is a single-replacement reaction. Hope this helps!

You might be interested in

The teal line of the hydrogen emission spectrum has a wavelength of 486.0 nm. A hydrogen emission spectrum has a violet, a blue,

Sloan [31]

Answer:

The correct answer to the following question will be "4.08 × 10⁻¹⁹ Joule".

Explanation:

Given:

Wavelength, λ = 486.0 nm

As we know,

$E=h\upsilon =\frac{hc}{\lambda}$

On putting the estimated values, we get

⇒ $=\frac{1241.5 \ ev\ nm}{486 \ nm}$

⇒ $=2.554 \ ev$

∴ 1 ev = 1.6 × 10⁻¹⁹ J

Now,

Energy, $E=2.554\times 1.6\times 10^{-19}$

⇒ $=4.08\times 10^{-19} Joule$

7 0

3 years ago

each of the following reactions has been reported in the chemical literature. predict the product in each case, showing stereoch

poizon [28]

(a): This is an elimination reaction. The reaction proceeds in 3 steps; Step 1: Protonation of alcohol, step 2: Loss of leaving group, and step 3: Deprotonation to form an alkene. Elimination (E1) reaction dominates than substitution (SN1) reaction because the formed HSO4- anion is a poor nucleophile and tends not to add to the carbocation intermediate formed. Hence the product formed is I, is trans.

(b) This is a dihydroxylation of the alkenes reaction. A catalytic amount of OsO4 is used along with an oxidizing agent, which oxidizes the reduced osmium(VI) into osmium(VIII) to regenerate the catalyst. The reaction proceeds in 2 steps; Step 1: Cis addition of OsO4 to double bond and form 4 member cyclic osmate ester. Step 2: Hydrolysis of the intermediate to 1.2-diol. Hence the product formed is II, is cis.

(c) This is hydroboration - oxidation reaction. The reaction proceeds through the addition of H- on the more substituted carbon and BH2 on the less substituted carbon of the double bond. The reaction is a syn addition. Hence the product formed is III.

(d) This a reduction reaction where carboxylic acid (-COOH) is reduced to 1o alcohol (-CH2OH). Hence the formed product is IV.

Stereochemistry, a subdiscipline of chemistry, involves the take a look at the relative spatial association of atoms that form the shape of molecules and their manipulation.

The observation of stereochemistry specializes in stereoisomers, which by means of definition have an equal molecular method and series of bonded atoms (constitution), however, differ within the three-dimensional orientations of their atoms in space. for that reason, it's also referred to as 3-d chemistry three-dimensionality.

Learn more about Stereochemistry here:-brainly.com/question/13266152

#SPJ4

Disclaimer:- your question is incomplete, please see below for the complete question.

Each of the following reactions has been reported in the chemical literature. Predict the product in each case, showing stereochemistry where appropriate.