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Olenka [21]
4 years ago
13

Which of the following is not a concern regarding the use of corn as biofuel

Chemistry
2 answers:
Lady_Fox [76]4 years ago
5 0
The color of corn is different than the color of gasoline or coal.
Sever21 [200]4 years ago
4 0

The correct answer for above statement is:

The color of corn is different than the color of gasoline or coal.

Explanation:

While there was a great potential to use grain as a biofuel the cost of corn-based commodities rushed up throughout the world as well as any other goods as more area was being given to corn. The only difficulty though is corn isn't the best specialist for biofuels, there are a lot of additional choices that work great and aren't as costly to grow.

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What is a characteristic of every combination reaction?
Scilla [17]
A combination reaction<span> is a </span>reaction<span> in which two reactants combine to form one product. It is also called a synthesis reaction. A characteristic to this type of reaction would be that there would always be only one product. Hope this answers the question. Have a nice day. </span>
7 0
3 years ago
Balance the equations.<br> Zn+ HCl →<br> ZnCl2 +
motikmotik

Answer:

Zn + 2HCl → ZnCl2 + H2

Explanation:

Zn + HCl → ZnCl2 +

The complete equation is given below:

Zn+ HCl → ZnCl2 + H2

Now we can balance the equation by doing the following:

There are 2 atoms of Cl and 2 atoms of H on the left. This can be balanced by putting 2 in front of HCl as shown below:

Zn + 2HCl → ZnCl2 + H2

7 0
4 years ago
A) week 1<br><br> b) week 2<br><br> c) week 3<br><br> d) week 4
nalin [4]
Try c I think is the most accurate one
4 0
3 years ago
Read 2 more answers
The value of the equilibrium constant for the following chemical equation is Kr 40 at 25°C. Calculate the solubility of Al(OH)s(
dedylja [7]

Answer:

0,040 M

Explanation:

The global reaction of the problem is:

Al(OH) (s) + OH⁻ ⇄ Al(OH)₂⁻(aq) K= 40

The equation of equilibrium is:

K = \frac{[Al(OH)_{2} ^-]}{[Al(OH)][OH^-]}

The concentration of OH⁻ is:

pOH = 14 - pH = <em>3</em>

pOH = -log [OH⁻]

[OH⁻] = 1x10⁻³

Thus:

40 = \frac{[Al(OH)_{2} ^-]}{[Al(OH)][1x10^{-3}]}

<em>0,04M =  \frac{[Al(OH)_{2} ^-]}{[Al(OH)]}</em>

This means that 0,04 M are the number of moles that the solvent can dissolve in 1L, in other words, solubility.

I hope it helps!

7 0
3 years ago
Solve the 3 questions
Dmitrij [34]

Answer:

what kind of math is this

Explanation:

5 0
3 years ago
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