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Olenka [21]
3 years ago
11

Balance the equations. Zn+ HCl → ZnCl2 +

Chemistry
1 answer:
motikmotik3 years ago
7 0

Answer:

Zn + 2HCl → ZnCl2 + H2

Explanation:

Zn + HCl → ZnCl2 +

The complete equation is given below:

Zn+ HCl → ZnCl2 + H2

Now we can balance the equation by doing the following:

There are 2 atoms of Cl and 2 atoms of H on the left. This can be balanced by putting 2 in front of HCl as shown below:

Zn + 2HCl → ZnCl2 + H2

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What procedure could a student use to examine an intensive property of a rectangular block of wood
photoshop1234 [79]

An intensive property does not change when you take away some of the sample. The procedures that a student could use to examine the intensive property of a rectangular block of wood are the hardness, color, density and molecular weight.

8 0
4 years ago
How many formula units are in 239.2g of <br> Br2<br> MgCl2<br> H2O<br> Fe
Oksana_A [137]

The formula units in the substances are as follows:

  • Br2 = 8.99 × 10^23 formula units
  • MgCl2 = 1.51 × 10^24 formula units
  • H2O = 2.57 × 10^24 formula units
  • Fe = 2.57 × 10^24 formula units

<h3>How many moles are in 239.2 g of the given substances?</h3>

The moles of the substances are determined from their molar mass.

Molar mass of the substances is given as follows:

  • Br2 = 160 g/mol
  • MgCl2 = 95 g/mol
  • H2O = 18 g/mol
  • Fe = 56 g/mol

Formula units = mass/molar mass × 6.02 × 10^23

The formula units in the substances are as follows:

  • Br2 = 239.2/160 × 6.02 × 10^23 = 8.99 × 10^23 formula units
  • MgCl2 = 239.2/95 × 6.02 × 10^23 = 1.51 × 10^24 formula units
  • H2O = 239.2/18 × 6.02 × 10^23 = 2.57 × 10^24 formula units
  • Fe = 239.2/56 × 6.02 × 10^23 = 2.57 × 10^24 formula units

In conclusion, the number of formula units is derived from the moles and Avogadro number.

Learn more about formula units at: brainly.com/question/24529075

#SPJ1

6 0
2 years ago
Pls helpits rlly hard
victus00 [196]

Answer:

5: 0.16

6: 50

Explanation:

Question 5:

We can use the equation density = mass/ volume.

We already have the mass (12g), but now we need to find the volume of the cylinder.

The equation for this is πr²h

So we know the radius is 2 and the height is 6.

π x (2)² x 6 = 24π = 75.398cm³

Now we can use the density equation above:

12/75.398 = 0.1592g/cm³ = 0.16g/cm³.

Question 6:

This time, we have to rearrange the equation density = mass/ volume to find the mass.

We know mass = density x volume.

From the question, the density is 2.5g/mL and the volume is 20mL.

Following the equation above, we do 2.5 x 20 to get 50g.

5 0
3 years ago
How can you tell what is what and how that what affects what
VLD [36.1K]

Answer:

Hi, this is a super vague question, so its pretty confusing to answer.  Could you please be a bit more specific?

If you are referring to chemistry, then how you tell "what is what" is by the molecular makeup of an element (Periodic table), and "how that..affects what", chemical reactions can occur between elements

8 0
3 years ago
Read 2 more answers
Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a
GrogVix [38]

Answer:

The calorie content of  65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

 ⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium)  + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41  * (65/15) = 326.78 cal

8 0
3 years ago
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