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Olenka [21]
3 years ago
11

Balance the equations. Zn+ HCl → ZnCl2 +

Chemistry
1 answer:
motikmotik3 years ago
7 0

Answer:

Zn + 2HCl → ZnCl2 + H2

Explanation:

Zn + HCl → ZnCl2 +

The complete equation is given below:

Zn+ HCl → ZnCl2 + H2

Now we can balance the equation by doing the following:

There are 2 atoms of Cl and 2 atoms of H on the left. This can be balanced by putting 2 in front of HCl as shown below:

Zn + 2HCl → ZnCl2 + H2

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Which of the following explanations accounts for the fact that the ion-solvent interaction is greater for Li than for K
OLEGan [10]

Li+ has a smaller ionic radius than K+

and smaller molecules have more collisions/interactions between each other

<h3>What is ion-solvent interaction ?</h3>

In the case of ion-solvent interactions, the state in which the interac-tions exist is an obvious one; it is the situation in which ions are inside the solvent.

  • Ions are charged particles, and charges interact with other charges. So there will also be ion-ion, as well as ion-solvent, interactions in the solution.

  • In the process of solvation, ions are surrounded by a concentric shell of solvent. Solvation is the process of reorganizing solvent and solute molecules into solvation complexes.

Learn more about Ion-solvent interaction here:

brainly.com/question/21307101

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6 0
1 year ago
What are the SI units of frequency?
Tomtit [17]
SI unit of frequency is Hertz(Hz)
7 0
3 years ago
Which two human activities are believed to be the greatest contributors to global warming?
vivado [14]
B. Deforestation and burning of fossil fuels. <span />
7 0
3 years ago
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On the basis of the information above, a buffer with a pH = 9 can best be made by using
telo118 [61]

Answer:

D H2PO4– + HPO42–

Explanation:

The acid dissociation constant for \mathbf{H_3PO_4 , H_2PO^{-}_4 ,  HPO_4^{2-}} are \mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \  5\times 10^{-13}} respectively.

\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}

\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}

\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}

The reason while option D is the best answer is that, the value of pKa for both

\mathbf{H_2PO^{-}_4 ,\  \& \  HPO_4^{2-}} lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.

Using Henderson-Hasselbach equation:

\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}

3 0
3 years ago
What tool is used in an explosion site to chemically detect explosive residues on objects?
qaws [65]

Answer:

ion mobility spectrometer

Explanation:

it is an handheld chemical dectection device

Hope this helps

Please mark me as Brainliest

8 0
3 years ago
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