Answer:
mark as brainliest pls
Explanation:
Hematite can be described as a rock which contains a lot of iron. Hematite is an ore of iron from which substantial amount of iron can be won at profit depending on prevailing economic conditions in a place
Answer:
![pH=13](https://tex.z-dn.net/?f=pH%3D13)
Explanation:
Hello,
In this case, given the acid, we can suppose a simple dissociation as:
![HA\rightleftharpoons H^+ + A^-](https://tex.z-dn.net/?f=HA%5Crightleftharpoons%20H%5E%2B%20%2B%20A%5E-)
Which occurs in aqueous phase, therefore, the law of mass action is written by:
![Ka=\frac{[H^+][A^-]}{[HA]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
That in terms of the change
due to the reaction's extent we can write:
![1x10^{-20}=\frac{x*x}{0.1M-x}](https://tex.z-dn.net/?f=1x10%5E%7B-20%7D%3D%5Cfrac%7Bx%2Ax%7D%7B0.1M-x%7D)
But we prefer to compute the Kb due to its exceptional weakness:
![Kb=\frac{Kw}{Ka}=\frac{1x10^{-14}}{1x10^{-20}} =1x10^{-6}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7BKw%7D%7BKa%7D%3D%5Cfrac%7B1x10%5E%7B-14%7D%7D%7B1x10%5E%7B-20%7D%7D%20%20%3D1x10%5E%7B-6%7D)
Next, the acid dissociation in the presence of the base we have:
![Kb=\frac{[OH^-][HA]}{[A^-]}=1x10^{6}=\frac{x*x}{0.1-x}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BOH%5E-%5D%5BHA%5D%7D%7B%5BA%5E-%5D%7D%3D1x10%5E%7B6%7D%3D%5Cfrac%7Bx%2Ax%7D%7B0.1-x%7D)
Whose solution is
which equals the concentration of hydroxyl in the solution, thus we compute the pOH:
![pOH=-log([OH^-])=-log(0.0999)=1](https://tex.z-dn.net/?f=pOH%3D-log%28%5BOH%5E-%5D%29%3D-log%280.0999%29%3D1)
Finally, since the maximum scale is 14, we can compute the pH by knowing the pOH:
![pH+pOH=14\\\\pH=14-pOH=14-1\\\\pH=13](https://tex.z-dn.net/?f=pH%2BpOH%3D14%5C%5C%5C%5CpH%3D14-pOH%3D14-1%5C%5C%5C%5CpH%3D13)
Regards.
We are using the General gas equation P x V/K = P x V/K
1. P = 1atm V=500ml so PxV= 500 at 6.5km P = 0.5atm V = ? so P xV = 0.5 x V
(We don't have to worry about temperature!) 500 = 0.5 x V so V = 1000ml
2. NO CHANGE in pressure here so we have V/K V=2.75 K = 20 + 273=293 so V/K= 2.75/293
Next set V = 2.46 K = ? so V/K = 2.46/K then 2.75/293= 2.46/K so K=(293/2.75)x2.46
=262 K
Convert back to Celsius 262 - 273 = -11 C
It's raining so I have to rescue the laundry!
Laundry rescued!
3.Now we have to use all three variables. I am using 273K and 100kPa for STP.
P = 100 V = 700 K = 273 These are altered P - unknown, V = 200 K = 273+30=303
!00 x 700/273 = 256.4 this is equal to P x 200/303 = P x 0.66
so P = 256.4/0.66 = 388.48kPa
When studying the
movement of heat, what does the term "system" refer to any quantity
of matter of fixed identity of the chosen study. “Surroundings" refer to
the rest of the universe beyond the boundary of your chosen study or system.